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Question

Red-green colour blindness is inherited as a recessive X-linked trait.

What will be the probability of having the colour-blind daughter to a phenotypically normal woman, who already had one colour-blind son, and is married to a colour-blind man?

The correct answer is
$50$%

Colour Blindness Inheritance Explained

Red-green colour blindness is an X-linked recessive trait. This means the gene responsible is on the X chromosome. Females (XX) must inherit two copies of the recessive allele (XcXc) to be affected, while males (XY) only need one (XcY).

Parental Genotype Determination

We determine the genotypes based on the information given:

  • Father: He is colour-blind. As it's X-linked, his genotype is definitively XcY.
  • Mother: She is phenotypically normal but has had a colour-blind son (XcY). This son received his Xc chromosome from his mother. Since she is normal, she must also have a normal allele (XC). Thus, her genotype is XCXc (she is a carrier).

Probability Calculation via Genetic Cross

The genetic cross is between the mother (XCXc) and the father (XcY). We can use a Punnett square to visualize the possible offspring genotypes:

Mother's Gametes
XC Xc
Father's Gametes Xc XCXc (Daughter, normal phenotype) XcXc (Daughter, colour-blind phenotype)
Y XCY (Son, normal phenotype) XcY (Son, colour-blind phenotype)

We need the probability of a colour-blind daughter. A colour-blind daughter has the genotype XcXc.

  • Looking at the possible daughter genotypes (XCXc and XcXc), one out of the two possibilities results in a colour-blind daughter.
  • The probability of inheriting Xc from the mother is 1/2.
  • The probability of inheriting Xc from the father is 1.
  • The probability of a daughter being XcXc is $(1/2) \times 1 = 1/2$.

Final Probability Result

The probability of having a colour-blind daughter is 50%.

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Important Questions from Mendelian Inheritance

  1. Mendel's 'law of segregation' applies to the segregation of __________ during gamete formation.
  2. Fabry disease in humans is a X-linked disease. The probability (in percentage) for a phenotypically normal father and a carrier mother to have a son with Fabry disease is ________.
  3. The allele associated with albinism in humans is recessive ($c$). The probability that an albino male ($cc$) and a carrier female ($Cc$) will have an offspring with normal skin pigmentation is _________. 

    (Round off to one decimal place)

  4. The blood group of the mother is A⁺ and that of the father is AB⁺. Which of the following statements is/are correct?
  5. Assuming independent assortment and no recombination, the number of different combinations of maternal and paternal chromosomes in gametes of an organism with a diploid number of 12 is ________.
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