What will be the HCF of 0.25 and 1.25?
0.25
The Highest Common Factor (HCF) of two or more numbers is the largest number that divides all of them exactly. When dealing with decimal numbers, the easiest way to find their HCF is to convert them into integers.
To find the HCF of 0.25 and 1.25, we can follow these steps:
Let's apply the steps to find the HCF of 0.25 and 1.25.
Step 1: Convert to whole numbers
Now we need to find the HCF of 25 and 125.
Step 2: Find the HCF of 25 and 125
We can find the HCF using methods like prime factorization or listing factors.
Using Prime Factorization:
The common prime factor is 5. The lowest power of the common prime factor is $5^2$.
So, HCF(25, 125) = $5^2 = 25$.
Alternatively, by listing factors:
The common factors are 1, 5, and 25. The largest common factor is 25.
So, HCF(25, 125) = 25.
Step 3: Divide the HCF by the power of 10
We found the HCF of 25 and 125 is 25. We multiplied the original numbers by 100.
HCF(0.25, 1.25) = $\frac{\text{HCF}(25, 125)}{100} = \frac{25}{100} = 0.25$
Therefore, the HCF of 0.25 and 1.25 is 0.25.
| Decimal Numbers | Multiplied by 100 | Resulting Integers | HCF of Integers | HCF of Decimals (HCF of Integers / 100) |
|---|---|---|---|---|
| 0.25 | $\times 100$ | 25 | 25 | 0.25 |
| 1.25 | $\times 100$ | 125 |
| Concept | Explanation | Example |
|---|---|---|
| HCF (Highest Common Factor) | The largest number that divides two or more numbers without leaving a remainder. Also known as the Greatest Common Divisor (GCD). | HCF(12, 18) = 6 |
| Finding HCF of Integers | Methods include prime factorization or listing all factors and finding the largest common one. | For HCF(25, 125): Factors of 25 are 1, 5, 25. Factors of 125 are 1, 5, 25, 125. Common factors are 1, 5, 25. HCF is 25. |
| Finding HCF of Decimals | Convert decimals to integers by multiplying by a power of 10, find the HCF of integers, then divide the result by the same power of 10. | HCF(0.2, 0.4): Convert to 2, 4. HCF(2, 4) = 2. Divide by 10: 2/10 = 0.2. So HCF(0.2, 0.4) = 0.2. |
Finding the HCF of numbers, whether integers or decimals, is a fundamental concept in number theory with various applications, including simplifying fractions and solving problems involving division.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?