What will be the average of all the even numbers between 5 and 29?
17
The question asks for the average of all even numbers that are greater than 5 and less than 29. To find the average, we first need to identify these even numbers and then use the formula for calculating the average.
Even numbers are integers that are perfectly divisible by 2. We need to list all even numbers that fall strictly between 5 and 29.
The sequence of even numbers between 5 and 29 is:
6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28
One way to calculate the average is to sum all the numbers in the sequence and then divide by the total count of numbers.
The sequence of even numbers (6, 8, 10, ..., 28) is an arithmetic progression because the difference between consecutive terms is constant (which is 2). For an arithmetic progression, the average is simply the average of the first and the last term.
Both methods yield the same result. The average of all even numbers between 5 and 29 is 17.
Let's compare our calculated average with the given options:
| Option | Value |
|---|---|
| 1 | 14 |
| 2 | 22 |
| 3 | 19 |
| 4 | 17 |
Our calculated average, 17, matches Option 4.
| Concept | Description | Example |
|---|---|---|
| Even Number | An integer divisible by 2. | 2, 4, 6, 8, ... |
| Average (Mean) | Sum of values divided by the count of values. | Average of 2, 4, 6 is \((2+4+6)/3 = 12/3 = 4\). |
| Arithmetic Progression | A sequence where the difference between consecutive terms is constant. | 6, 8, 10, 12 (common difference is 2). |
| Average of AP | (First term + Last term) / 2 | Average of 6, 8, 10, 12 is \((6+12)/2 = 18/2 = 9\). Also, \((6+8+10+12)/4 = 36/4 = 9\). |
The average, also known as the mean, is a measure of central tendency. It gives us a single value that represents the center of a set of numbers.
In this problem, recognizing the even numbers between 5 and 29 formed an arithmetic progression allowed for a quicker calculation of the average using the first and last terms.
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