What will be the angle between the hour hand & the minute hand of a clock when the time is 5:36 AM?
48°
Understanding how to calculate the angle between the hour hand and the minute hand of a clock involves knowing their relative speeds and positions at a given time. Let's break down the process for 5:36 AM.
At 36 minutes past the hour, the minute hand's position is calculated based on its speed from the 12 o'clock mark.
Minute hand position = Minutes $\times$ Speed of minute hand
Minute hand position = $36 \times 6^{\circ}/\text{minute}$
Minute hand position = $216^{\circ}$ from the 12.
The hour hand's position depends on both the hour and the minutes past the hour. At 5:00, the hour hand is exactly at the 5. Each hour mark is $30^{\circ}$ apart ($360^{\circ}/12$). The hour hand moves an additional amount based on the minutes.
At 5:36 AM:
Hour hand position = $(5 \times 30^{\circ}) + (36 \times 0.5^{\circ})$
Hour hand position = $150^{\circ} + 18^{\circ}$
Hour hand position = $168^{\circ}$ from the 12.
The angle between the hour hand and the minute hand is the absolute difference between their positions.
Angle = $\mid \text{Hour hand position} - \text{Minute hand position} \mid$
Angle = $\mid 168^{\circ} - 216^{\circ} \mid$
Angle = $\mid -48^{\circ} \mid$
Angle = $48^{\circ}$
The angle between the hands is $48^{\circ}$. Since $48^{\circ}$ is less than $180^{\circ}$, this is the smaller angle. If the result were greater than $180^{\circ}$, we would subtract it from $360^{\circ}$ to find the smaller angle.
Let's summarize the positions:
| Hand | Position Calculation | Angle from 12 |
|---|---|---|
| Minute Hand | $36 \times 6^{\circ}/\text{minute}$ | $216^{\circ}$ |
| Hour Hand | $(5 \times 30^{\circ}) + (36 \times 0.5^{\circ})$ | $168^{\circ}$ |
The difference in angles is $|216^{\circ} - 168^{\circ}| = 48^{\circ}$.
| Clock Part | Movement in 1 minute | Movement in 1 hour |
|---|---|---|
| Minute Hand | $6^{\circ}$ | $360^{\circ}$ |
| Hour Hand | $0.5^{\circ}$ | $30^{\circ}$ |
Remember these speeds are crucial for solving clock angle problems for any given time.
You can use a general formula to find the angle between clock hands at H hours and M minutes:
Angle = $\mid (30 \times \text{H}) - (11/2 \times \text{M}) \mid$
Or, expressed differently:
Angle = $\mid (30 \times \text{H}) - (5.5 \times \text{M}) \mid$
Let's check this for 5:36 AM (H=5, M=36):
Angle = $\mid (30 \times 5) - (5.5 \times 36) \mid$
Angle = $\mid 150 - 198 \mid$
Angle = $\mid -48 \mid$
Angle = $48^{\circ}$
This formula gives the same result and is a quick way to calculate the angle between the hour hand and the minute hand.
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