At what angle are the hour and minute hands of a clock inclined at 15 minutes past 5?
67½°
This problem asks us to find the angle between the hour hand and the minute hand of a standard clock at a specific time: 15 minutes past 5, which is 5:15.
To solve this, we need to understand how fast each hand moves around the clock face. The clock face is a circle, covering 360 degrees.
The minute hand completes a full circle (360°) in 60 minutes.
At 15 minutes past 5, the minute hand has moved 15 minutes past the 12 position. The angle of the minute hand from the 12 is:
The minute hand is pointing exactly at the '3'.
The hour hand completes a full circle (360°) in 12 hours. First, let's find its speed per hour:
Since there are 60 minutes in an hour, its speed per minute is:
At 5:15, the hour hand has moved past the '5' position because 15 minutes have passed since 5:00. At exactly 5:00, the hour hand would be at the '5'. The angle of the '5' mark from the 12 is $5 \times 30^\circ = 150^\circ$.
In the 15 minutes past 5, the hour hand moves an additional angle:
So, the total angle of the hour hand from the 12 at 5:15 is:
To find the angle between the hour and minute hands, we find the absolute difference between their angles from the 12 mark.
The difference is:
The angle $67.5^\circ$ is the same as $67\frac{1}{2}^\circ$.
Therefore, at 15 minutes past 5 (5:15), the hour and minute hands of a clock are inclined at an angle of 67.5 degrees or 67½ degrees.
| Hand | Speed per hour | Speed per minute |
|---|---|---|
| Minute Hand | $360^\circ$ | $6^\circ$ |
| Hour Hand | $30^\circ$ | $0.5^\circ$ |
| Concept | Formula/Value | Explanation |
|---|---|---|
| Total degrees on clock face | $360^\circ$ | A full circle |
| Degrees between numbers (12 to 1, 1 to 2, etc.) | $30^\circ$ | $360^\circ / 12$ hours |
| Minute hand speed | $6^\circ$/minute | $360^\circ / 60$ minutes |
| Hour hand speed | $0.5^\circ$/minute | $30^\circ / 60$ minutes |
| Angle of minute hand from 12 at M minutes past H | $6M^\circ$ | Angle measured clockwise |
| Angle of hour hand from 12 at H hours and M minutes | $(30H + 0.5M)^\circ$ | Angle measured clockwise |
| Angle between hands | $|Hour\ Hand\ Angle - Minute\ Hand\ Angle|$ | Absolute difference |
Clock angle problems are common in aptitude tests. They require you to calculate the relative positions of the hour and minute hands at a specific time.
The key is to determine the angle of each hand relative to the 12 o'clock position (usually taken as $0^\circ$) and then find the difference. Remember that the hour hand moves continuously, not just on the hour marks. Its position depends on both the hour and the number of minutes past the hour.
Sometimes, the calculated angle might be greater than $180^\circ$. In such cases, the smaller angle between the hands is usually requested, which would be $360^\circ - \text{calculated angle}$. In this specific problem, the calculated angle $67.5^\circ$ is less than $180^\circ$, so it is the direct answer.
Understanding the speeds of the hands ($6^\circ$ per minute for the minute hand and $0.5^\circ$ per minute for the hour hand) is fundamental to solving these problems accurately.
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