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Question

The data of installed capacity of electricity produced by different sources of energy (solar, wind and coal) in two states (X) and (Y) alongwith their respective populations are given for the years 2011 and 2021 in the table given below. Based on the data, answer the following questions:

Statewise details of population and installed capacity of electricity

State XState Y
Year

Population

(mn)

Solar

(GW)

Wind

(GW)

Coal

(GW)

Population

(mn)

Solar

(GW)

Wind

(GW)

Coal

(GW)

20115020104060150850
20216028154268201055

What was the per capita availability of electricity in state X in the year 2021?

The correct answer is ∼ 1.41 kW

Understanding Per Capita Electricity Availability

The question asks us to calculate the per capita availability of electricity in State X for the year 2021. Per capita availability means the amount of a resource (in this case, electricity generation capacity) available per person in a given population. To find this, we need two key pieces of information from the provided table:

  1. The total installed capacity of electricity generation in State X in 2021.
  2. The population of State X in 2021.

Extracting Data for State X in 2021

Let's look at the data provided for State X in the year 2021:

Year Population (mn) Solar (GW) Wind (GW) Coal (GW)
2021 60 28 15 42

From this table, we gather the following data for State X in 2021:

  • Population: 60 million (mn)
  • Installed Solar Capacity: 28 GW
  • Installed Wind Capacity: 15 GW
  • Installed Coal Capacity: 42 GW

Calculating Total Installed Capacity in State X (2021)

The total installed capacity is the sum of the capacities from all listed sources (Solar, Wind, and Coal) in State X for the year 2021.

Total Installed Capacity (GW) = Solar Capacity + Wind Capacity + Coal Capacity

Total Installed Capacity (GW) = \(28 \text{ GW} + 15 \text{ GW} + 42 \text{ GW}\)

Total Installed Capacity (GW) = \(85 \text{ GW}\)

Converting Units for Per Capita Calculation

The question asks for per capita availability in kilowatts (kW). The total installed capacity is currently in gigawatts (GW), and the population is in millions (mn).

We need to convert GW to kW and million people to the total number of people.

  • 1 GW = \(10^6\) kW (1 Gigawatt = 1,000,000 kilowatts)
  • 1 million = \(10^6\)

Total Installed Capacity in kW = \(85 \text{ GW} \times 10^6 \text{ kW/GW} = 85 \times 10^6 \text{ kW}\)

Population in 2021 = \(60 \text{ mn} = 60 \times 10^6 \text{ people}\)

Calculating Per Capita Availability of Electricity

Now we can calculate the per capita availability of electricity in kW by dividing the total installed capacity in kW by the total population.

Per Capita Availability (kW/person) = \(\frac{\text{Total Installed Capacity (kW)}}{\text{Population (people)}}\)

Per Capita Availability (kW/person) = \(\frac{85 \times 10^6 \text{ kW}}{60 \times 10^6 \text{ people}}\)

Notice that the \(10^6\) terms cancel out, simplifying the calculation:

Per Capita Availability (kW/person) = \(\frac{85}{60} \text{ kW/person}\)

Now, we perform the division:

\(\frac{85}{60} = \frac{17 \times 5}{12 \times 5} = \frac{17}{12}\)

\(\frac{17}{12} \approx 1.4166...\)

Rounding to two decimal places, this is approximately 1.42 kW/person. However, the options provided are rounded to different decimal places. Let's check the options against the calculated value \(\approx 1.4166...\).

  • Option 1: \(\sim 1.21 \text{ kW}\) (Not close)
  • Option 2: \(\sim 1.41 \text{ kW}\) (Very close to 1.4166...)
  • Option 3: \(\sim 1.25 \text{ kW}\) (Not close)
  • Option 4: \(\sim 1.62 \text{ kW}\) (Not close)

The calculated value \(1.4166...\) is closest to \(1.41\).

Therefore, the per capita availability of electricity in State X in the year 2021 was approximately 1.41 kW.

Summary of Calculation Steps

  1. Identify the required data (Total Installed Capacity and Population for State X in 2021).
  2. Sum up the installed capacities from all sources to get the total capacity in GW.
  3. Convert total capacity from GW to kW.
  4. Convert population from millions to the total number of people.
  5. Divide the total capacity in kW by the total population to find the per capita availability in kW per person.
  6. Compare the calculated value with the given options.

Revision Table: Key Data Points

Parameter Value for State X (2021)
Population 60 million (60 × 106 people)
Solar Capacity 28 GW
Wind Capacity 15 GW
Coal Capacity 42 GW
Total Installed Capacity 85 GW (85 × 106 kW)
Per Capita Availability \( \frac{85 \times 10^6 \text{ kW}}{60 \times 10^6 \text{ people}} \approx 1.41 \text{ kW/person} \)

Additional Information: Energy Capacity and Per Capita Metrics

Installed Capacity: This refers to the maximum power output that a power plant or set of power plants can produce under specific conditions. It's a measure of potential generation, not necessarily actual electricity generated over a period (which is measured in kWh or GWh).

Per Capita Availability: This metric helps understand the potential access to electricity for each individual in a population based on the installed capacity. Higher per capita installed capacity often correlates with higher electricity consumption and potentially a higher standard of living, although factors like grid infrastructure and actual generation/demand play crucial roles.

Units:

  • Watt (W): Basic unit of power.
  • Kilowatt (kW): 1 kW = 1,000 W = \(10^3\) W
  • Megawatt (MW): 1 MW = 1,000 kW = \(10^6\) W
  • Gigawatt (GW): 1 GW = 1,000 MW = \(10^9\) W

Converting between units is essential for calculations involving different scales of energy capacity.

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Important Questions from Tabulation

  1. The table shows District-wise data of a number of primary school teachers posted in schools of a city.

    Study the table and answer the question:

    District

    Male teachers

    Female teachers

    East

    1650

    2375

    North

    1075

    2651

    West

    1280

    1520

    South

    1170

    1085

    Central

    690

    859


    What is the difference between the total number of male teachers in the districts East, North, West taken together and the total number of female teachers in the districts East and South?
  2. Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

    Suresh

    Nitin

    Varun

    Salary

    35000

    38500

    29000

    42000

    Arrears

    6000

    6300

    5000

    7500

    Bonus

    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    What is the ratio of salary of Varun to his income other than salary?
  3. Study the table and answer the question:

    Income (Rs.)

    No. of persons

    Less than 200

    12

    Less than 250

    26

    Less than 300

    34

    Less than 350

    40

    Less than 400

    50


    What is the percentage of persons earning Rs. 250 or more?
  4. The following table shows the annual profit of a company (in Rs. lakh).

    2014-2015

    2015-2016

    2016-0217

    2017-2018

    2018-2019

    625

    690

    725

    775

    815

    The period which has the maximum percentage increase in profit over the previous year is:

  5. The table given below shows the number of persons participating in a survey from 6 different states.

    States Persons 
    S1100
    S2200 
    S3400 
    S4500 
    S5600 
    S6800

    What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?

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