This question requires calculating the initial amount of money (Principal Sum, P) invested or borrowed, given the Simple Interest (SI) earned, the Rate of Interest (R), and the Time Period (T).
The fundamental formula for Simple Interest is:
$SI = \frac{P \times R \times T}{100}$
To determine the Principal Sum (P), we rearrange this formula:
$P = \frac{SI \times 100}{R \times T}$
Substitute the provided values into the rearranged formula:
$P = \frac{700 \times 100}{8 \times 2}$
First, calculate the numerator and the denominator:
$P = \frac{70000}{16}$
Now, perform the division:
$P = 4375$
Therefore, the sum of money that will yield ₹700 as simple interest in 2 years at 8% per annum is ₹4375.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?