Assume $R$ is measured in Ohms ($\Omega$), $L$ in meters ($m$), and $A$ in square meters ($m^2$).
The question asks us to determine the standard International System of Units (SI) unit for specific resistance, often denoted by the Greek letter rho ($\rho$). We are given the relationship between electrical resistance ($R$), the material's length ($L$), its uniform cross-sectional area ($A$), and its specific resistance ($\rho$):
$R = \rho \frac{L}{A}$
We are also provided with the standard SI units for the other quantities involved:
To find the unit of specific resistance ($\rho$), we need to rearrange the given formula to isolate $\rho$. Multiplying both sides by $A$ and dividing by $L$, we get:
$\rho = R \frac{A}{L}$
Now, we can substitute the SI units of $R$, $A$, and $L$ into the rearranged formula to find the unit of $\rho$.
Unit of $\rho$ = (Unit of $R$) $\times$ (Unit of $A$) / (Unit of $L$)
Substituting the given units:
Unit of $\rho$ = $\Omega \times \frac{m^2}{m}$
Simplifying the expression:
Unit of $\rho$ = $\Omega \times m$
Therefore, the standard SI unit for specific resistance ($\rho$) is Ohm-meter, which is written as $\Omega \cdot m$. This unit correctly reflects the relationship between resistance, length, and area for a given material.
Comparing this result with the given options, the correct unit for specific resistance is Ohm-meter ($\Omega \cdot m$).
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