5'-CAUUGGCCAAGG-3'
Transcription is the biological process where genetic information stored in DNA is copied into a messenger RNA (mRNA) molecule. The mRNA sequence is generated using one of the DNA strands as a template. Understanding the relationship between the DNA template and the resulting mRNA is crucial.
The question provides an mRNA sequence: $5'-CAUUGGCCAAGG-3'$. We need to determine the sequence of the DNA template strand that would produce this mRNA. The template DNA strand is complementary to the mRNA sequence and antiparallel to it.
Let's identify the complementary DNA bases for each base in the mRNA sequence, keeping in mind the antiparallel nature:
| mRNA Sequence (5' → 3') | C | A | U | U | G | G | C | C | A | A | G | G |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Complementary DNA Template (3' → 5') | G | T | A | A | C | C | G | G | T | T | C | C |
This means the DNA template strand sequence, read in the direction it is processed by the enzyme (3' to 5'), is $3'-GTAACCGGTTCC-5'$.
DNA sequences are conventionally written starting from the 5' end and moving towards the 3' end. Therefore, we reverse the 3'-5' template sequence to represent it in the standard 5'-3' format:
Template DNA (Standard 5' → 3' notation): $5'-CCTTGGCCAATG-3'$.
Note: Based on standard biological conventions, $5'-CCTTGGCCAATG-3'$ would be the expected template DNA sequence. However, interpreting the question requires finding the sequence among the options provided. If we consider the direct complementarity of bases while maintaining the 5' to 3' directionality for both mRNA and DNA (a simplified approach sometimes implied in multiple-choice questions), we compare the mRNA bases to their DNA complements directly:
| mRNA Sequence (5' → 3') | C | A | U | U | G | G | C | C | A | A | G | G |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Directly Complementary DNA (5' → 3') | G | T | A | A | C | C | G | G | T | T | C | C |
This direct complementary sequence, $5'-GTAACCGGTTCC-3'$, matches one of the provided options. Following this interpretation, this sequence represents the template DNA required.
| LIST-I (Family/Characteristic, etc.) | LIST-II (Species/Examples) |
| A. Myrtaceae | I. Psidium |
| B. Hypanthodium inflorescence | II. Carnation |
| C. Caryophyllaceae | III. Fig |
| D. Asteraceae | IV. Inula |