The following table shows the number of males (M) and females (F) (in thousands) in Towns X and Y during the five years from 2018 to 2022. Based on the data in the table, answer the questions. Year wise numbers of Males and Females in two Towns (in thousands) Years Town X Town Y Number of males Number of females Number of males Number of females 2018 50 49 53 50 2019 52 49 54 52 2020 55 52 55 54 2021 53 53 58 56 2022 55 52 62 55
What is the ratio of the average number of males in Town X to the average number of males in Town Y for males the given period?
265 ∶ 282
The question asks us to find the ratio of the average number of males in Town X to the average number of males in Town Y over the given five years, from 2018 to 2022. To do this, we first need to calculate the average number of males for each town.
The provided table gives the number of males and females (in thousands) for both towns across the five years. Let's extract the data for males in Town X and Town Y.
| Year | Town X (Males) | Town Y (Males) |
|---|---|---|
| 2018 | 50 | 53 |
| 2019 | 52 | 54 |
| 2020 | 55 | 55 |
| 2021 | 53 | 58 |
| 2022 | 55 | 62 |
To find the average number of males in Town X, we sum the number of males for each year from 2018 to 2022 and then divide by the number of years, which is 5.
Sum of Males in Town X = Number of males in 2018 + 2019 + 2020 + 2021 + 2022
\begin{equation*} \text{Sum of Males in Town X} = 50 + 52 + 55 + 53 + 55 \end{equation*}
\begin{equation*} \text{Sum of Males in Town X} = 265 \text{ (in thousands)} \end{equation*}
Now, we calculate the average by dividing the sum by 5:
\begin{equation*} \text{Average Males in Town X} = \frac{\text{Sum of Males in Town X}}{\text{Number of Years}} \end{equation*}
\begin{equation*} \text{Average Males in Town X} = \frac{265}{5} \end{equation*}
\begin{equation*} \text{Average Males in Town X} = 53 \text{ (in thousands)} \end{equation*}
Next, we do the same for Town Y. Sum the number of males for each year from 2018 to 2022.
Sum of Males in Town Y = Number of males in 2018 + 2019 + 2020 + 2021 + 2022
\begin{equation*} \text{Sum of Males in Town Y} = 53 + 54 + 55 + 58 + 62 \end{equation*}
\begin{equation*} \text{Sum of Males in Town Y} = 282 \text{ (in thousands)} \end{equation*}
Calculate the average by dividing the sum by 5:
\begin{equation*} \text{Average Males in Town Y} = \frac{\text{Sum of Males in Town Y}}{\text{Number of Years}} \end{equation*}
\begin{equation*} \text{Average Males in Town Y} = \frac{282}{5} \end{equation*}
\begin{equation*} \text{Average Males in Town Y} = 56.4 \text{ (in thousands)} \end{equation*}
The question asks for the ratio of the average number of males in Town X to the average number of males in Town Y.
Ratio = Average Males in Town X ∶ Average Males in Town Y
\begin{equation*} \text{Ratio} = \frac{265}{5} : \frac{282}{5} \end{equation*}
To express this ratio in its simplest integer form, we can multiply both parts of the ratio by the denominator, which is 5.
\begin{equation*} \text{Ratio} = \left(\frac{265}{5} \times 5\right) : \left(\frac{282}{5} \times 5\right) \end{equation*}
\begin{equation*} \text{Ratio} = 265 : 282 \end{equation*}
The ratio of the average number of males in Town X to the average number of males in Town Y is 265 ∶ 282.
Based on the calculations, the ratio of the average number of males in Town X to the average number of males in Town Y for the given period is 265 ∶ 282.
| Metric | Town X | Town Y |
|---|---|---|
| Sum of Males (2018-2022) | 265 | 282 |
| Number of Years | 5 | 5 |
| Average Males | $ \frac{265}{5} = 53 $ | $ \frac{282}{5} = 56.4 $ |
| Ratio of Averages (Town X : Town Y) | $ 53 : 56.4 $ or $ \frac{265}{5} : \frac{282}{5} \implies 265 : 282 $ | |
Data interpretation questions often require extracting specific data points from tables, charts, or graphs and performing calculations like sums, averages, percentages, or ratios. Key skills include:
Ratio problems involve comparing two quantities. A ratio $a:b$ can also be written as a fraction $\frac{a}{b}$. When comparing averages calculated over the same number of items (like years in this case), the ratio of the sums is equal to the ratio of the averages: $\frac{\text{Sum}_X}{\text{count}} : \frac{\text{Sum}_Y}{\text{count}} \implies \text{Sum}_X : \text{Sum}_Y$.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?