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Question

What is the probability of having children with 'O' blood group, where both mother and father are heterozygous for 'A' and 'B' blood group, respectively ?

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
25%

Blood Group Probability Calculation

This question involves basic Mendelian genetics, specifically the ABO blood group system, which has three alleles: $I^A$, $I^B$, and $i$ (often represented as $I^O$). Alleles $I^A$ and $I^B$ are codominant, and both are dominant over $i$. Blood group 'O' has the genotype $ii$ ($I^O I^O$).

Determining Parental Genotypes

The mother is heterozygous for 'A' blood group. This means her genotype is $I^A i$ ($I^A I^O$). She has the 'A' antigen but also carries the recessive 'O' allele.

The father is heterozygous for 'B' blood group. This means his genotype is $I^B i$ ($I^B I^O$). He has the 'B' antigen but also carries the recessive 'O' allele.

Predicting Offspring Genotypes

We can use a Punnett square to determine the possible genotypes of the offspring. Each parent can produce two types of gametes:

  • Mother: $I^A$ and $i$ ($I^O$)
  • Father: $I^B$ and $i$ ($I^O$)
$I^B$ $i$ ($I^O$)
$I^A$ $I^A I^B$ $I^A i$ ($I^A I^O$)
$i$ ($I^O$) $I^B i$ ($I^B I^O$) $i i$ ($I^O I^O$)

Identifying the 'O' Blood Group Probability

The Punnett square shows four possible genotypes for the offspring:

  • $I^A I^B$ (Blood Group AB)
  • $I^A i$ ($I^A I^O$) (Blood Group A)
  • $I^B i$ ($I^B I^O$) (Blood Group B)
  • $i i$ ($I^O I^O$) (Blood Group O)

Each genotype has an equal probability of occurring, which is 1 out of 4, or 25%.

The genotype required for blood group 'O' is $ii$ ($I^O I^O$). This occurs in 1 out of the 4 possible combinations.

Therefore, the probability of having a child with blood group 'O' is 25%.

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Important Questions from Genetics

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