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Question

What is the mean of the following distribution?
Marks1333517683
No. of Students5313242316

The correct answer is
42

Calculating the Mean of a Frequency Distribution

The mean of a frequency distribution represents the average value of the data. It is calculated using the formula:

$ \text{Mean} (\bar{x}) = \frac{\sum (f \cdot x)}{\sum f} $

In this formula, '$f$' represents the frequency of each data point (here, 'No. of Students'), and '$x$' represents the value of the data point (here, 'Marks'). The term '$ \sum (f \cdot x) $' signifies the sum of the products of each frequency and its corresponding value, while '$ \sum f $' represents the total sum of all frequencies.

Data Analysis

The data provided in the question is as follows:

  • Marks (x): 13, 33, 35, 17, 68, 3, 16
  • No. of Students (f): 5, 3, 1, 3, 2, 4, 2, 3, 1, 6

Note on Data Consistency: It's important to notice that there are 7 distinct 'Marks' values listed, but there are 10 'No. of Students' (frequency) values. For a standard frequency distribution calculation, the number of values should match the number of frequencies. We will proceed by assuming that the first 7 frequency values correspond directly to the 7 listed marks, as this is a common approach when encountering such discrepancies.

Step-by-Step Calculation

1. Organize the Data: We'll create a table to list the Marks (x), the corresponding No. of Students (f), and calculate the product (f * x) for each pair.

Marks (x) No. of Students (f) Product (f * x)
13 5 65
33 3 99
35 1 35
17 3 51
68 2 136
3 4 12
16 2 32
Total 20 430

2. Sum of Frequencies ($ \sum f $): Add up the frequencies from the table.

$ \sum f = 5 + 3 + 1 + 3 + 2 + 4 + 2 = 20 $

3. Sum of Products ($ \sum (f \cdot x) $): Add up the values in the 'Product (f * x)' column.

$ \sum (f \cdot x) = 65 + 99 + 35 + 51 + 136 + 12 + 32 = 430 $

4. Calculate the Mean: Apply the mean formula using the sums calculated.

$ \bar{x} = \frac{\sum (f \cdot x)}{\sum f} = \frac{430}{20} $

$ \bar{x} = 21.5 $

Final Result

Based on the standard calculation method applied to the provided data (and interpreting the frequency list as described), the calculated mean for this distribution is 21.5. This value is derived directly from the marks and the corresponding frequencies.

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Important Questions from Elementary Statistics (Notes)

  1. Let $X_1, X_2, X_3$ be a random sample of size 3 from an absolutely continuous distribution that is symmetric about 0. For $i=1,2,3$, let $R_i$ denote the rank of $|X_i|$ among $|X_1|, |X_2|$ and $|X_3|$. 

    If $T^+ = \sum_{i=1, X_i>0}^3 R_i$

     is the Willcoxon signed-rank statistic, then which of the following statements are true?, 

  2. Which of the following is the first step in calculating the median of data set?
    1. Average the middle two values of the data set
    2. Array the data
    3. Determine the relative weights of the data values in terms of importance
    4. Find the average distance of the observations in the data set from the mean
  3. If the median of a data is 61.54 less than its mode, then the median of the data exceeds its mean by _____. (Use the empirical formula to find the answer)
  4. The mean marks of the following distribution is:

    Marks Obtained   No. of Students
    8115
    354
    733
    5616
  5. The geometric mean of 100 observations is 25. If each observation is multiplied by 4, what will be the new geometric mean?
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