We are given the relationship between the median and mode:
Median = Mode - 61.54
This can be rewritten as:
Mode = Median + 61.54
The empirical relationship between mean, median, and mode for moderately skewed distributions is:
$Mode = 3 \times Median - 2 \times Mean$
Substitute the expression for the mode from the given information into the empirical formula:
$Median + 61.54 = 3 \times Median - 2 \times Mean$
Now, rearrange the equation to find the difference between the median and the mean (Median - Mean):
$2 \times Mean = 3 \times Median - Median - 61.54$
$2 \times Mean = 2 \times Median - 61.54$
$2 \times Median - 2 \times Mean = 61.54$
$2 \times (Median - Mean) = 61.54$
$Median - Mean = \frac{61.54}{2}$
$Median - Mean = 30.77$
Therefore, the median of the data exceeds its mean by 30.77.
Let $X_1, X_2, X_3$ be a random sample of size 3 from an absolutely continuous distribution that is symmetric about 0. For $i=1,2,3$, let $R_i$ denote the rank of $|X_i|$ among $|X_1|, |X_2|$ and $|X_3|$.
If $T^+ = \sum_{i=1, X_i>0}^3 R_i$
is the Willcoxon signed-rank statistic, then which of the following statements are true?,
The mean marks of the following distribution is:
| Marks Obtained | No. of Students |
| 81 | 15 |
| 35 | 4 |
| 73 | 3 |
| 56 | 16 |