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What is the LCM of \(x^4+x^2y^2 + y^4\), \(x^3y+y^4\) and \(x^4y^2 - x^3 y^3\)?

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is
\(x^3y^2 (x^6-y^6)\)

Factoring the Algebraic Expressions

To find the Least Common Multiple (LCM) of the given expressions, we first need to factor each expression completely.

Expression 1: \(x^4+x^2y^2 + y^4\)

This expression can be factored by adding and subtracting \(x^2y^2\) to complete the square:

  • \(x^4+x^2y^2 + y^4 = (x^4 + 2x^2y^2 + y^4) - x^2y^2\)
  • \(= (x^2+y^2)^2 - (xy)^2\)
  • Using the difference of squares formula (\(a^2 - b^2 = (a-b)(a+b)\)):
  • \(= (x^2+y^2 - xy)(x^2+y^2 + xy)\)
  • Rearranging the terms within the factors:
  • \(= (x^2 - xy + y^2)(x^2 + xy + y^2)\)

Expression 2: \(x^3y+y^4\)

Factor out the common term \(y\):

  • \(x^3y+y^4 = y(x^3+y^3)\)
  • Using the sum of cubes formula (\(a^3+b^3 = (a+b)(a^2-ab+b^2)\)):
  • \(= y(x+y)(x^2 - xy + y^2)\)

Expression 3: \(x^4y^2 - x^3 y^3\)

Factor out the common term \(x^3y^2\):

  • \(x^4y^2 - x^3 y^3 = x^3y^2(x - y)\)

Finding the LCM

The LCM is found by taking the highest power of each unique factor present in the factorizations of the expressions.

The unique factors are:

  • \(x^3\) (highest power from Expression 3)
  • \(y^2\) (highest power from Expression 3)
  • \((x-y)\) (from Expression 3)
  • \((x+y)\) (from Expression 2)
  • \((x^2 - xy + y^2)\) (present in Expressions 1 and 2, highest power is 1)
  • \((x^2 + xy + y^2)\) (from Expression 1)

Multiplying these factors together gives the LCM:

LCM \(= x^3 \cdot y^2 \cdot (x-y) \cdot (x+y) \cdot (x^2 - xy + y^2) \cdot (x^2 + xy + y^2)\)

Simplifying the LCM Expression

We can simplify the product of factors using algebraic identities:

  • Recall the difference of cubes: \(a^3 - b^3 = (a-b)(a^2+ab+b^2)\).
  • Recall the sum of cubes: \(a^3 + b^3 = (a+b)(a^2-ab+b^2)\).
  • Also, recall the difference of sixth powers: \(a^6 - b^6 = (a^3)^2 - (b^3)^2 = (a^3 - b^3)(a^3 + b^3)\).
  • Substituting the factored forms of cubes:
  • \(x^6 - y^6 = [(x-y)(x^2+xy+y^2)] \cdot [(x+y)(x^2-xy+y^2)]\)
  • Rearranging the terms, we see that \((x-y)(x+y)(x^2-xy+y^2)(x^2+xy+y^2)\) is exactly the product of the polynomial factors we found.

Therefore, the LCM can be written as:

LCM \(= x^3 y^2 (x^6 - y^6)\)

Conclusion

By factoring each polynomial and identifying the highest power of all unique factors, we determined the LCM. The LCM of \(x^4+x^2y^2 + y^4\), \(x^3y+y^4\), and \(x^4y^2 - x^3 y^3\) is \(x^3y^2 (x^6 - y^6)\).

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  2. What is the HCF of \(2^{36}-1\) and \(2^{45}-1\)?
  3. The HCF of \(x\) and \(y\) is \(H\). Consider the following statements in respect of the HCF of \(p=\frac{x^3 + y^3}{x^2-xy+y^2}\) and \(q=\frac{x^3-y^3}{x^2+xy+y^2}\) : 

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Important Questions from LCM and HCF

  1. The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:

  2. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

  3. Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?

  4. What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?

  5. Which of the following is a pair of co-primes?

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