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Question

What is the electronic configuration of rhodium?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^2 \text{3p}^6 \text{3d}^{10} \text{4s}^2 \text{4p}^6 \text{4d}^8 \text{5s}^1$

Rhodium Electronic Configuration Details

Rhodium (Rh) is a chemical element with atomic number 45. It is a transition metal.

The electronic configuration of an element describes the arrangement of electrons in its atomic orbitals. We determine this based on the Aufbau principle, Hund's rule, and the Pauli exclusion principle, noting exceptions for stability.

The noble gas that precedes Rhodium in the periodic table is Krypton (Kr). Kr has 36 electrons. Its configuration is:

$ \text{Kr}: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 $

Rhodium has 9 more electrons than Krypton ($45 - 36 = 9$). These electrons are added to the subsequent energy levels, primarily the 4d and 5s orbitals.

Transition metals like Rhodium often exhibit exceptions to the standard filling order to achieve greater stability. For Rhodium, the most stable configuration is achieved by having one electron in the 5s orbital and eight electrons in the 4d orbital.

Therefore, the complete electronic configuration of Rhodium (Rh) is:

$ \text{Rh}: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^8 5s^1 $

This configuration accurately represents the electron distribution in Rhodium atoms and matches the details provided in Option A.

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