Study the given table carefully and answer the question that follows : The following table gives the marks obtained by 6 students in 6 different subjects in an examination. Note: The number in the bracket gives the maximum marks in each subject. Subject (Max Marks) Student Physics (100) Chemistry (100) Math (100) History (50) Computer Science (50) Hindi (50) A 80 76 68 40 36 24 B 90 68 72 42 38 26 C 85 81 75 38 32 31 D 75 79 58 28 28 34 E 45 65 62 31 29 28 F 68 72 68 26 34 30
What is the difference of percentage in the total marks of students D and E?
9.34
This question requires us to use the data provided in the table to calculate the total percentage marks obtained by two students, D and E, and then find the difference between these percentages.
The table presents the marks secured by 6 students (A to F) across 6 different subjects. The maximum marks for each subject are indicated in brackets next to the subject name.
| Subject (Max Marks) | Physics (100) | Chemistry (100) | Math (100) | History (50) | Computer Science (50) | Hindi (50) |
|---|---|---|---|---|---|---|
| Student A | 80 | 76 | 68 | 40 | 36 | 24 |
| Student B | 90 | 68 | 72 | 42 | 38 | 26 |
| Student C | 85 | 81 | 75 | 38 | 32 | 31 |
| Student D | 75 | 79 | 58 | 28 | 28 | 34 |
| Student E | 45 | 65 | 62 | 31 | 29 | 28 |
| Student F | 68 | 72 | 68 | 26 | 34 | 30 |
To find the overall percentage, we first need to determine the total maximum marks possible across all subjects. We sum the maximum marks for each subject:
Maximum Marks for Physics: 100
Maximum Marks for Chemistry: 100
Maximum Marks for Math: 100
Maximum Marks for History: 50
Maximum Marks for Computer Science: 50
Maximum Marks for Hindi: 50
Total Maximum Marks \( = 100 + 100 + 100 + 50 + 50 + 50 = 450 \)
Next, we sum the marks obtained by student D in all subjects:
Total Marks for Student D \( = 75 + 79 + 58 + 28 + 28 + 34 = 302 \)
Similarly, we sum the marks obtained by student E in all subjects:
Total Marks for Student E \( = 45 + 65 + 62 + 31 + 29 + 28 = 260 \)
The percentage marks are calculated using the formula:
\[ \text{Percentage} = \frac{\text{Total Marks Obtained}}{\text{Total Maximum Marks}} \times 100 \]
Percentage for Student D:
\[ \text{Percentage D} = \frac{302}{450} \times 100 \]
\[ \text{Percentage D} = \frac{30200}{450} = \frac{3020}{45} = \frac{604}{9} \]
Percentage for Student E:
\[ \text{Percentage E} = \frac{260}{450} \times 100 \]
\[ \text{Percentage E} = \frac{26000}{450} = \frac{2600}{45} = \frac{520}{9} \]
We need to find the difference between the percentage marks of Student D and Student E.
Difference \( = \text{Percentage D} - \text{Percentage E} \)
\[ \text{Difference} = \frac{604}{9} - \frac{520}{9} = \frac{604 - 520}{9} = \frac{84}{9} = \frac{28}{3} \]
Now, we convert the fraction to a decimal:
\[ \frac{28}{3} \approx 9.3333... \]
Rounding this value to two decimal places, or comparing with the given options, the difference is approximately 9.34.
| Calculation Step | Value |
|---|---|
| Total Maximum Marks | 450 |
| Total Marks (Student D) | 302 |
| Total Marks (Student E) | 260 |
| Percentage (Student D) | \(\frac{302}{450} \times 100 \approx 67.11\%\) |
| Percentage (Student E) | \(\frac{260}{450} \times 100 \approx 57.78\%\) |
| Difference in Percentage | \(\approx 9.34\%\) |
Calculating the difference in percentages is a common task in data analysis. It helps in comparing the performance or value between two entities relative to a whole.
In this case, the percentage difference shows how much higher Student D's overall performance percentage is compared to Student E's overall performance percentage in the examination. It is calculated by subtracting the lower percentage from the higher percentage.
It's important to calculate the individual percentages first and then find the difference, rather than finding the difference in raw scores and then calculating the percentage of that difference relative to the total maximum marks (unless specified otherwise, as "difference of percentage" implies subtraction of percentages).
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?