What is Sin θ tan θ - sec θ ? A. -cos θ B. 1 C. -sec θ D. cosec θ
A
This question asks us to simplify a given trigonometric expression: $\sin \theta \tan \theta - \sec \theta$. To simplify this expression, we can use fundamental trigonometric identities to rewrite the terms in terms of $\sin \theta$ and $\cos \theta$.
Let's break down the terms in the expression:
Now, let's substitute the identities for $\tan \theta$ and $\sec \theta$ into the given expression:
The expression is: $\sin \theta \tan \theta - \sec \theta$
Substitute $\tan \theta = \frac{\sin \theta}{\cos \theta}$ and $\sec \theta = \frac{1}{\cos \theta}$:
$$ \sin \theta \left( \frac{\sin \theta}{\cos \theta} \right) - \frac{1}{\cos \theta} $$
Multiply the terms in the first part:
$$ \frac{\sin^2 \theta}{\cos \theta} - \frac{1}{\cos \theta} $$
Now we have two terms with a common denominator, $\cos \theta$. We can combine them:
$$ \frac{\sin^2 \theta - 1}{\cos \theta} $$
Recall the fundamental Pythagorean identity: $\sin^2 \theta + \cos^2 \theta = 1$.
We can rearrange this identity to find an expression for $\sin^2 \theta - 1$. Subtracting 1 from both sides gives:
$$ \sin^2 \theta + \cos^2 \theta - 1 = 1 - 1 $$
$$ \sin^2 \theta + \cos^2 \theta - 1 = 0 $$
Subtracting $\cos^2 \theta$ from both sides gives:
$$ \sin^2 \theta - 1 = -\cos^2 \theta $$
Now, substitute this into our simplified expression:
$$ \frac{-\cos^2 \theta}{\cos \theta} $$
We can cancel one $\cos \theta$ term from the numerator and the denominator, assuming $\cos \theta \neq 0$:
$$ \frac{-\cos \theta \cdot \cos \theta}{\cos \theta} = -\cos \theta $$
So, the simplified expression is $-\cos \theta$.
Let's compare our result with the given options:
A. $-\cos \theta$
B. $1$
C. $-\sec \theta$
D. $\cosec \theta$
Our simplified expression $-\cos \theta$ matches option A.
| Step | Expression | Explanation |
|---|---|---|
| 1 | $\sin \theta \tan \theta - \sec \theta$ | Starting expression |
| 2 | $\sin \theta \left( \frac{\sin \theta}{\cos \theta} \right) - \frac{1}{\cos \theta}$ | Substitute $\tan \theta = \frac{\sin \theta}{\cos \theta}$ and $\sec \theta = \frac{1}{\cos \theta}$ |
| 3 | $\frac{\sin^2 \theta}{\cos \theta} - \frac{1}{\cos \theta}$ | Simplify the first term |
| 4 | $\frac{\sin^2 \theta - 1}{\cos \theta}$ | Combine terms with common denominator |
| 5 | $\frac{-\cos^2 \theta}{\cos \theta}$ | Use identity $\sin^2 \theta - 1 = -\cos^2 \theta$ |
| 6 | $-\cos \theta$ | Cancel $\cos \theta$ term |
The simplification process shows that $\sin \theta \tan \theta - \sec \theta$ simplifies to $-\cos \theta$.
| Identity Type | Identity | Notes |
|---|---|---|
| Reciprocal | $\sec \theta = \frac{1}{\cos \theta}$ | Used to express $\sec \theta$ in terms of $\cos \theta$. |
| Reciprocal/Ratio | $\tan \theta = \frac{\sin \theta}{\cos \theta}$ | Used to express $\tan \theta$ in terms of $\sin \theta$ and $\cos \theta$. |
| Pythagorean | $\sin^2 \theta + \cos^2 \theta = 1$ | Fundamental identity used here in the form $\sin^2 \theta - 1 = -\cos^2 \theta$. |
Simplifying trigonometric expressions is a common task in trigonometry. It often involves using fundamental identities to rewrite expressions in a simpler form, usually in terms of $\sin \theta$ and $\cos \theta$. Here are some tips:
Understanding these basic steps and identities is crucial for solving more complex trigonometric problems.
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