What is \(\frac{{1 - \tan 2^\circ \cot 62^\circ }}{{\tan 152^\circ - \cot 88^\circ }}\) equal to?
-√3
We need to evaluate the given trigonometric expression:
\[ \frac{{1 - \tan 2^\circ \cot 62^\circ }}{{\tan 152^\circ - \cot 88^\circ }} \]
Let's simplify the numerator and the denominator separately using trigonometric identities and angle properties.
The denominator is \( \tan 152^\circ - \cot 88^\circ \). We can rewrite the angles using standard transformations:
Substituting these back into the denominator:
\[ \tan 152^\circ - \cot 88^\circ = (-\tan 28^\circ) - (\tan 2^\circ) = -(\tan 28^\circ + \tan 2^\circ) \]
The numerator is \( 1 - \tan 2^\circ \cot 62^\circ \). We can rewrite \( \cot 62^\circ \):
Substituting this back into the numerator:
\[ 1 - \tan 2^\circ \cot 62^\circ = 1 - \tan 2^\circ \tan 28^\circ \]
Now substitute the simplified numerator and denominator back into the original expression:
\[ \frac{{1 - \tan 2^\circ \cot 62^\circ }}{{\tan 152^\circ - \cot 88^\circ }} = \frac{{1 - \tan 2^\circ \tan 28^\circ}}{{-(\tan 28^\circ + \tan 2^\circ)}} \]
We can rewrite this as:
\[ - \frac{{1 - \tan 2^\circ \tan 28^\circ}}{{\tan 2^\circ + \tan 28^\circ}} \]
Recall the tangent addition formula: \( \tan(A + B) = \frac{{\tan A + \tan B}}{{1 - \tan A \tan B}} \). Taking the reciprocal, we get \( \cot(A + B) = \frac{{1 - \tan A \tan B}}{{\tan A + \tan B}} \).
Comparing the expression \( \frac{{1 - \tan 2^\circ \tan 28^\circ}}{{\tan 2^\circ + \tan 28^\circ}} \) with the \( \cot(A + B) \) formula, we can set \( A = 2^\circ \) and \( B = 28^\circ \).
So, \( \frac{{1 - \tan 2^\circ \tan 28^\circ}}{{\tan 2^\circ + \tan 28^\circ}} = \cot(2^\circ + 28^\circ) = \cot(30^\circ) \).
The value of \( \cot(30^\circ) \) is \( \sqrt{3} \).
Substituting this back into our full expression:
\[ - \cot(30^\circ) = -\sqrt{3} \]
Thus, the value of the given expression is \( -\sqrt{3} \).
| Identity | Description |
|---|---|
| \( \tan(180^\circ - \theta) = -\tan \theta \) | Tangent of an angle in the second quadrant. |
| \( \cot(90^\circ - \theta) = \tan \theta \) | Cotangent of a complementary angle. |
| \( \cot(A + B) = \frac{{1 - \tan A \tan B}}{{\tan A + \tan B}} \) | Reciprocal of the tangent addition formula. |
| \( \cot(30^\circ) = \sqrt{3} \) | Exact value of cotangent for 30 degrees. |
Understanding angle transformations (like \( 90^\circ \pm \theta \), \( 180^\circ \pm \theta \), etc.) is crucial for simplifying trigonometric expressions. These transformations allow us to relate trigonometric functions of angles outside the first quadrant to functions of acute angles.
For example:
Knowing the exact values of trigonometric functions for standard angles like \( 0^\circ, 30^\circ, 45^\circ, 60^\circ, 90^\circ \) (and their multiples) is also essential. These values often appear in simplified expressions.
| Angle (\( \theta \)) | \( \tan \theta \) | \( \cot \theta \) |
|---|---|---|
| \( 30^\circ \) | \( \frac{1}{\sqrt{3}} \) | \( \sqrt{3} \) |
| \( 45^\circ \) | \( 1 \) | \( 1 \) |
| \( 60^\circ \) | \( \sqrt{3} \) | \( \frac{1}{\sqrt{3}} \) |
By combining angle transformations and fundamental identities, complex expressions can often be reduced to simple values.
What is cos 2β equal to ?
What is the value of sec2γ?
On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get
(1 – sin A + cos A) 2is equal to
What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?