All Exams Test series for 1 year @ ₹349 only
Question

On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get

The correct answer is

3

Simplifying Trigonometric Expressions Using Identities

We are asked to simplify the given trigonometric expression:

\(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\)

To simplify this expression, we will use the triple angle identities for sine and cosine:

  • \(\sin 3{\rm{A}} = 3\sin {\rm{A}} - 4{\sin ^3}{\rm{A}}\)
  • \(\cos 3{\rm{A}} = 4{\cos ^3}{\rm{A}} - 3\cos {\rm{A}}\)

Let's simplify the first term of the expression:

Simplifying the First Term: \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}}\)

Substitute the identity for \(\sin 3{\rm{A}}\) into the numerator:

\(\sin^3 {\rm{A}} + \sin 3{\rm{A}} = \sin^3 {\rm{A}} + (3\sin {\rm{A}} - 4\sin^3 {\rm{A}})\)

\(= 3\sin {\rm{A}} + \sin^3 {\rm{A}} - 4\sin^3 {\rm{A}}\)

\(= 3\sin {\rm{A}} - 3\sin^3 {\rm{A}}\)

\(= 3\sin {\rm{A}} (1 - \sin^2 {\rm{A}})\)

Now, substitute this back into the first term expression (assuming \(\sin {\rm{A}} \neq 0\)):

\(\frac{{3\sin {\rm{A}} (1 - \sin^2 {\rm{A}})}}{{\sin {\rm{A}}}}\)

\(= 3 (1 - \sin^2 {\rm{A}})\)

Using the Pythagorean identity \(\sin^2 {\rm{A}} + \cos^2 {\rm{A}} = 1\), we know that \(1 - \sin^2 {\rm{A}} = \cos^2 {\rm{A}}\).

So, the first term simplifies to:

\(= 3 \cos^2 {\rm{A}}\)

Simplifying the Second Term: \(\frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\)

Substitute the identity for \(\cos 3{\rm{A}}\) into the numerator:

\(\cos^3 {\rm{A}} - \cos 3{\rm{A}} = \cos^3 {\rm{A}} - (4\cos^3 {\rm{A}} - 3\cos {\rm{A}})\)

\(= \cos^3 {\rm{A}} - 4\cos^3 {\rm{A}} + 3\cos {\rm{A}}\)

\(= 3\cos {\rm{A}} - 3\cos^3 {\rm{A}}\)

\(= 3\cos {\rm{A}} (1 - \cos^2 {\rm{A}})\)

Now, substitute this back into the second term expression (assuming \(\cos {\rm{A}} \neq 0\)):

\(\frac{{3\cos {\rm{A}} (1 - \cos^2 {\rm{A}})}}{{\cos {\rm{A}}}}\)

\(= 3 (1 - \cos^2 {\rm{A}})\)

Using the Pythagorean identity \(\sin^2 {\rm{A}} + \cos^2 {\rm{A}} = 1\), we know that \(1 - \cos^2 {\rm{A}} = \sin^2 {\rm{A}}\).

So, the second term simplifies to:

\(= 3 \sin^2 {\rm{A}}\)

Adding the Simplified Terms:

The original expression is the sum of the simplified first and second terms:

\(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}} = 3 \cos^2 {\rm{A}} + 3 \sin^2 {\rm{A}}\)

\(= 3 (\cos^2 {\rm{A}} + \sin^2 {\rm{A}})\)

Using the Pythagorean identity \(\sin^2 {\rm{A}} + \cos^2 {\rm{A}} = 1\):

\(= 3 (1)\)

\(= 3\)

Thus, the simplified expression is 3.


Step Calculation Identity/Reason
1 First term: \(\frac{{\sin^3 {\rm{A}} + \sin 3{\rm{A}}}}{{\sin {\rm{A}}}}\) Given
2 Substitute \(\sin 3{\rm{A}}\) \(\sin 3{\rm{A}} = 3\sin {\rm{A}} - 4{\sin ^3}{\rm{A}}\)
3 \(\frac{{\sin^3 {\rm{A}} + (3\sin {\rm{A}} - 4\sin^3 {\rm{A}})}}{{\sin {\rm{A}}}}\) Substitution
4 \(\frac{{3\sin {\rm{A}} - 3\sin^3 {\rm{A}}}}{{\sin {\rm{A}}}}\) Combine terms
5 \(\frac{{3\sin {\rm{A}} (1 - \sin^2 {\rm{A}})}}{{\sin {\rm{A}}}}\) Factor out \(3\sin {\rm{A}}\)
6 \(3 (1 - \sin^2 {\rm{A}})\) Cancel \(\sin {\rm{A}}\) (assuming \(\sin {\rm{A}} \neq 0\))
7 \(3 \cos^2 {\rm{A}}\) \(1 - \sin^2 {\rm{A}} = \cos^2 {\rm{A}}\)
8 Second term: \(\frac{{\cos^3 {\rm{A}} - \cos 3{\rm{A}}}}{{\cos {\rm{A}}}}\) Given
9 Substitute \(\cos 3{\rm{A}}\) \(\cos 3{\rm{A}} = 4{\cos ^3}{\rm{A}} - 3\cos {\rm{A}}\)
10 \(\frac{{\cos^3 {\rm{A}} - (4\cos^3 {\rm{A}} - 3\cos {\rm{A}})}}{{\cos {\rm{A}}}}\) Substitution
11 \(\frac{{3\cos {\rm{A}} - 3\cos^3 {\rm{A}}}}{{\cos {\rm{A}}}}\) Combine terms
12 \(\frac{{3\cos {\rm{A}} (1 - \cos^2 {\rm{A}})}}{{\cos {\rm{A}}}}\) Factor out \(3\cos {\rm{A}}\)
13 \(3 (1 - \cos^2 {\rm{A}})\) Cancel \(\cos {\rm{A}}\) (assuming \(\cos {\rm{A}} \neq 0\))
14 \(3 \sin^2 {\rm{A}}\) \(1 - \cos^2 {\rm{A}} = \sin^2 {\rm{A}}\)
15 Total Expression = Term 1 + Term 2 Addition
16 \(3 \cos^2 {\rm{A}} + 3 \sin^2 {\rm{A}}\) Substitute results
17 \(3 (\cos^2 {\rm{A}} + \sin^2 {\rm{A}})\) Factor out 3
18 \(3 (1)\) \(\sin^2 {\rm{A}} + \cos^2 {\rm{A}} = 1\)
19 \(3\) Final Result

Revision Table: Key Trigonometric Identities

Identity Category Identity
Triple Angle for Sine \(\sin 3{\rm{A}} = 3\sin {\rm{A}} - 4{\sin ^3}{\rm{A}}\)
Triple Angle for Cosine \(\cos 3{\rm{A}} = 4{\cos ^3}{\rm{A}} - 3\cos {\rm{A}}\)
Pythagorean Identity \(\sin^2 {\rm{A}} + \cos^2 {\rm{A}} = 1\)

Additional Information: Understanding Trigonometric Simplification

Trigonometric simplification involves using various trigonometric identities to reduce a complex expression into a simpler form. This is a fundamental skill in trigonometry and is often required when solving equations, evaluating integrals, or analyzing periodic functions.

The identities used here, specifically the triple angle identities for \(\sin 3{\rm{A}}\) and \(\cos 3{\rm{A}}\), are derived from angle addition formulas. For example, \(\sin 3{\rm{A}} = \sin (2{\rm{A}} + {\rm{A}})\) can be expanded using the \(\sin(X+Y)\) formula and then further simplified using double angle identities (\(\sin 2{\rm{A}}\) and \(\cos 2{\rm{A}}\)). Mastering these core identities is crucial for simplifying more complex trigonometric expressions.

Always remember to note any restrictions on the variable \({\rm{A}}\), such as \(\sin {\rm{A}} \neq 0\) and \(\cos {\rm{A}} \neq 0\), which ensure the denominators are non-zero when simplifying by dividing. However, the final result '3' is a constant, implying the expression evaluates to 3 for all valid values of A where the original expression is defined.

Was this answer helpful?

Important Questions from Trigonometric Identities

  1. What is cos 2β equal to ?

  2. What is the value of sec2γ?

  3. (1 – sin A + cos A) 2is equal to

  4. What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?

  5. What is \(\frac{{1 - \tan 2^\circ \cot 62^\circ }}{{\tan 152^\circ - \cot 88^\circ }}\) equal to?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App