If x = sin 70° ⋅ sin 50° and y = cos 60° ⋅ cos 80°, then what is xy equal to?
1/16
Let's evaluate the given expressions for x and y and then find their product xy. We are given:
x = sin 70° ⋅ sin 50°
y = cos 60° ⋅ cos 80°
We will use the product-to-sum trigonometric identities to simplify the expressions for x and y.
The product-to-sum formula for two sine functions is:
\(2 \sin A \sin B = \cos(A - B) - \cos(A + B)\)
For x = sin 70° ⋅ sin 50°, let A = 70° and B = 50°. So, \(2x = 2 \sin 70° \sin 50°\).
Applying the formula:
\(2x = \cos(70° - 50°) - \cos(70° + 50°)\)
\(2x = \cos 20° - \cos 120°\)
We know that \(\cos 120° = \cos(180° - 60°) = -\cos 60°\). The value of \(\cos 60°\) is \(1/2\).
So, \(\cos 120° = -1/2\).
Substituting this value back into the equation for \(2x\):
\(2x = \cos 20° - (-1/2)\)
\(2x = \cos 20° + 1/2\)
Now, divide by 2 to find x:
\(x = \frac{1}{2} \cos 20° + \frac{1}{4}\)
The expression for y is given as:
\(y = \cos 60° \sdot \cos 80°\)
We know the exact value of \(\cos 60°\) is \(1/2\).
Substitute this value into the expression for y:
\(y = \frac{1}{2} \cos 80°\)
Now we need to find the product xy by multiplying the expressions we found for x and y:
\(xy = \left(\frac{1}{2} \cos 20° + \frac{1}{4}\right) \left(\frac{1}{2} \cos 80°\right)\)
Distribute the term \(\left(\frac{1}{2} \cos 80°\right)\) inside the first parenthesis:
\(xy = \left(\frac{1}{2} \cos 20°\right) \left(\frac{1}{2} \cos 80°\right) + \left(\frac{1}{4}\right) \left(\frac{1}{2} \cos 80°\right)\)
\(xy = \frac{1}{4} \cos 20° \cos 80° + \frac{1}{8} \cos 80°\)
We have a product of cosines term, \(\cos 20° \cos 80°\). Let's use another product-to-sum formula:
\(2 \cos A \cos B = \cos(A + B) + \cos(A - B)\)
For \(\cos 20° \cos 80°\), let A = 80° and B = 20° (order doesn't matter for the sum, but for difference, we can take the larger angle first to keep it positive, or remember \(\cos(-\theta) = \cos \theta\)). Let's use A=80°, B=20°:
\(2 \cos 80° \cos 20° = \cos(80° + 20°) + \cos(80° - 20°)\)
\(2 \cos 80° \cos 20° = \cos 100° + \cos 60°\)
We know \(\cos 60° = 1/2\). Also, \(\cos 100° = \cos(180° - 80°) = -\cos 80°\).
So, \(2 \cos 80° \cos 20° = -\cos 80° + 1/2\)
Divide by 2:
\(\cos 80° \cos 20° = \frac{1}{2} \left(-\cos 80° + \frac{1}{2}\right) = -\frac{1}{2} \cos 80° + \frac{1}{4}\)
Now substitute this back into the expression for xy:
\(xy = \frac{1}{4} \left(-\frac{1}{2} \cos 80° + \frac{1}{4}\right) + \frac{1}{8} \cos 80°\)
Distribute the \(1/4\):
\(xy = -\frac{1}{8} \cos 80° + \frac{1}{16} + \frac{1}{8} \cos 80°\)
The terms \(-\frac{1}{8} \cos 80°\) and \(+\frac{1}{8} \cos 80°\) cancel each other out.
\(xy = \frac{1}{16}\)
Thus, the value of xy is \(1/16\).
| Trigonometric Value | Value |
| \(\cos 60°\) | \(1/2\) |
| \(\cos 120°\) | \(-1/2\) |
| Concept | Description | Formula Example |
| Product-to-Sum | Identities that convert products of sines/cosines into sums/differences. | \(2 \sin A \sin B = \cos(A - B) - \cos(A + B)\) |
| Special Angle Values | Exact trigonometric values for common angles like 0°, 30°, 45°, 60°, 90°, etc. | \(\cos 60° = 1/2\) |
| Angle Relationships | How trig functions relate for angles like \(180° - \theta\) or \(-\theta\). | \(\cos(180° - \theta) = -\cos \theta\) |
Trigonometric identities are equations that are true for all values of the variables for which both sides of the equation are defined. They are crucial for simplifying expressions, solving equations, and evaluating exact values.
Common types of identities include:
Mastering these identities is key to success in trigonometry. The product-to-sum identities are particularly useful when dealing with products of sine and cosine functions and can often simplify expressions involving specific angles.
What is cos 2β equal to ?
What is the value of sec2γ?
On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get
What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?
What is the value of \(\left( {1 + \cos \frac{{\rm{\pi }}}{8}} \right)\left( {1 + \cos \frac{{3{\rm{\pi }}}}{8}} \right)\left( {1 + \cos \frac{{5{\rm{\pi }}}}{8}} \right)\left( {1 + \cos \frac{{7{\rm{\pi }}}}{8}} \right)?\)