Volume of a cuboid is 4800 cm 3. If the height of this cuboid is 20 cm, then what will be the area of the base of cuboid ?
240 cm 2
This problem involves finding the area of the base of a cuboid when its volume and height are known. A cuboid is a three-dimensional shape with six rectangular faces. The volume of a cuboid is calculated by multiplying its length, width, and height. The base of a cuboid is typically one of its rectangular faces, and its area is calculated by multiplying its length and width.
The relationship between the volume, base area, and height of a cuboid is given by the formula:
\(\text{Volume} = \text{Area of Base} \times \text{Height}\)
We are given the following information:
We need to find the area of the base of the cuboid. We can rearrange the formula for the volume of a cuboid to solve for the Area of Base:
\(\text{Area of Base} = \frac{\text{Volume}}{\text{Height}}\)
Now, let's substitute the given values into the rearranged formula:
\(\text{Area of Base} = \frac{4800 \text{ cm}^3}{20 \text{ cm}}\)
Performing the division:
\(\text{Area of Base} = 240 \text{ cm}^2\)
Therefore, the area of the base of the cuboid is 240 cm². The unit for area is square centimeters (cm²) because we divided volume (cm³) by height (cm), resulting in cm³ / cm = cm².
Let's verify this with the original formula:
Volume = Area of Base \(\times\) Height
Volume = 240 cm² \(\times\) 20 cm
Volume = 4800 cm³
This matches the given volume, confirming our calculation for the base area is correct.
| Measurement | Value | Unit |
|---|---|---|
| Volume | 4800 | cm³ |
| Height | 20 | cm |
| Area of Base | 240 | cm² |
The area of the base of the cuboid is 240 cm².
Let's quickly revise the key concepts related to cuboids, volume, and area that were used in solving this problem.
Understanding the different properties of a cuboid is important for solving geometry problems. Here is some additional information:
Knowing the relationship between volume, base area, and height allows us to calculate any one of these values if the other two are known, as demonstrated in this problem.
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