Two similar cubes have heights of 8 cm and 12 cm, respectively. If the capacity of the smaller cube is 80 cm 3, what is the capacity of the bigger cube (in cm 3)?
270
When we talk about similar cubes, we mean that they have the same shape but different sizes. In geometry, similar figures are figures that are proportional to each other. This means that the ratio of any two corresponding lengths in the figures is constant. This constant ratio is often called the scale factor.
For similar three-dimensional figures like cubes, the relationship between corresponding lengths, areas, and volumes (or capacity) is specific:
We are given two similar cubes with heights of 8 cm and 12 cm. The height of a cube is the same as its side length. Let's find the scale factor, which is the ratio of their corresponding heights.
Ratio of heights = \(\frac{\text{Height of smaller cube}}{\text{Height of bigger cube}}\)
Ratio of heights = \(\frac{8 \text{ cm}}{12 \text{ cm}}\)
Simplifying the fraction, we get:
Scale Factor = \(\frac{8}{12} = \frac{2}{3}\)
So, the scale factor from the smaller cube to the bigger cube is \(2/3\). This means every length in the smaller cube is \(2/3\) times the corresponding length in the bigger cube.
As mentioned, for similar figures, the ratio of their capacities (volumes) is the cube of the scale factor (ratio of corresponding lengths).
Ratio of Capacities = (Ratio of heights)³
Ratio of Capacities = \(\left(\frac{2}{3}\right)^3\)
Ratio of Capacities = \(\frac{2^3}{3^3} = \frac{8}{27}\)
This means the capacity of the smaller cube is \(8/27\) times the capacity of the bigger cube. We can write this as:
\(\frac{\text{Capacity of smaller cube}}{\text{Capacity of bigger cube}} = \frac{8}{27}\)
We are given that the capacity of the smaller cube is 80 cm³. We can use the ratio we just found to calculate the capacity of the bigger cube.
Let \(V_{smaller}\) be the capacity of the smaller cube and \(V_{bigger}\) be the capacity of the bigger cube.
\(\frac{V_{smaller}}{V_{bigger}} = \frac{8}{27}\)
Substitute the given value \(V_{smaller} = 80 \text{ cm}^3\):
\(\frac{80}{V_{bigger}} = \frac{8}{27}\)
Now, we can solve for \(V_{bigger}\) by cross-multiplying:
\(8 \times V_{bigger} = 80 \times 27\)
\(V_{bigger} = \frac{80 \times 27}{8}\)
\(V_{bigger} = 10 \times 27\)
\(V_{bigger} = 270\)
The capacity of the bigger cube is 270 cm³.
In this case:
| Ratio Type | Relationship to Scale Factor (\(k\)) | Example (k=2/3) |
|---|---|---|
| Ratio of Corresponding Lengths | \(k\) | \(2/3\) |
| Ratio of Corresponding Areas | \(k^2\) | \((2/3)^2 = 4/9\) |
| Ratio of Corresponding Volumes (Capacity) | \(k^3\) | \((2/3)^3 = 8/27\) |
Similar geometric figures maintain proportional relationships between all their corresponding parts. This principle applies not just to cubes, but to any similar polygons or polyhedra. For example, similar triangles, similar spheres, or similar cylinders follow the same ratio rules regarding lengths, areas, and volumes.
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