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Question

Varingon’s theorem of moments states that if a number of coplanar forces acting on a particle are in equilibrium, then

The correct answer is

the algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point

Understanding Varignon's Theorem

Varignon's theorem, also known as the Principle of Moments, is a fundamental concept in mechanics. It provides a way to relate the moment of a system of forces to the moment of their resultant force.

The theorem states that for a system of coplanar forces, the algebraic sum of the moments of these forces about any point in their plane is equal to the moment of their resultant force about the same point.

Mathematically, if we have a system of forces $\vec{F}_1, \vec{F}_2, ..., \vec{F}_n$ acting in a plane, and their resultant is $\vec{R} = \sum_{i=1}^n \vec{F}_i$, then for any point $O$ in the plane, the sum of the moments of the individual forces about $O$ is equal to the moment of the resultant force about $O$.

This can be written as:

$\sum_{i=1}^n (\vec{r}_i \times \vec{F}_i) = \vec{r}_R \times \vec{R}$

where $\vec{r}_i$ is the position vector from point $O$ to the point of application of force $\vec{F}_i$, and $\vec{r}_R$ is the position vector from point $O$ to the point of application of the resultant force $\vec{R}$ (if the resultant is represented by a single force passing through a specific point).

Let's examine the given options in the context of Varignon's theorem:

  • Option 1: "Their algebraic sum is zero" - This statement describes the condition for translational equilibrium ($\sum \vec{F} = 0$). While forces in equilibrium satisfy this, it is not the definition of Varignon's theorem.
  • Option 2: "Their lines of action are at equal distances" - This is generally not a condition related to Varignon's theorem or equilibrium.
  • Option 3: "The algebraic sum of their moments about any point in their plane is zero" - This statement describes the condition for rotational equilibrium ($\sum M = 0$). If forces are in equilibrium, both $\sum \vec{F} = 0$ and $\sum M = 0$ (about any point) are true. However, Varignon's theorem holds true for *any* system of coplanar forces, whether they are in equilibrium or not. It relates the sum of moments to the resultant's moment, not necessarily stating that the sum of moments is zero.
  • Option 4: "the algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point" - This statement is the correct and precise definition of Varignon's theorem.

Therefore, Varignon's theorem fundamentally states the relationship between the moments of individual forces and the moment of their resultant about the same point.

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Important Questions from Equilibrium and Friction

  1. If in a planar system, only 2 reaction forces are acting, then the system is:-

  2. By applying the static equations i.e. ∑H = 0, ∑V = 0 and ∑M = 0. To a determine structure, we may determine:

  3. Which of the following is not a type of equilibrium?

  4. A block of mass 4√2 kg is at rest on the inclined plane. The inclined plane is inclined at an angle of 135° from horizontal direction in anticlockwise direction. Determine the coefficient of friction so that block can start slide in downward direction, assume the acceleration of gravity as 10 m/s2.

  5. A block of mass 10 kg is sliding on the ground with applied external force of 20 N. The coefficient of friction between the block and the ground is 0.1. Determine the linear acceleration of the block. Assume the acceleration due to gravity as 10 m/s2 .

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