By applying the static equations i.e. ∑H = 0, ∑V = 0 and ∑M = 0. To a determine structure, we may determine:
All option are correct
Static equilibrium equations are fundamental principles used in engineering mechanics and structural analysis to determine unknown forces and moments acting on a structure or a body that is at rest (in a state of static equilibrium). These equations state that for a body to be in equilibrium, the net force and the net moment acting on it must be zero in all directions.
The three primary static equilibrium equations in a 2D plane are:
In 3D analysis, there are six equilibrium equations: $\sum F_x = 0$, $\sum F_y = 0$, $\sum F_z = 0$, $\sum M_x = 0$, $\sum M_y = 0$, and $\sum M_z = 0$. The question focuses on the general application, implying the core 2D equations or their 3D equivalents.
One of the primary uses of static equilibrium equations is to determine the unknown forces and moments exerted by the supports on a structure. These are called supporting reactions. By considering the entire structure as a free body and applying the equilibrium equations, we can solve for the reaction components, provided the structure is statically determinate. A statically determinate structure is one where all support reactions and internal forces can be determined using only the equations of static equilibrium.
Once the external forces, including the supporting reactions, are known, the static equilibrium equations can also be used to determine the internal forces within the structure. Internal forces include axial forces, shear forces, and bending moments at any point along the structural member.
To find internal forces like shear force and bending moment at a specific point, one conceptually cuts the structure at that point and considers either segment as a free body. By applying the static equilibrium equations ($\sum F_x = 0$, $\sum F_y = 0$, $\sum M = 0$) to this segment, the unknown internal forces and moments acting at the cut section can be determined.
Based on the application of the static equilibrium equations:
Therefore, applying the static equations allows us to determine supporting reactions, shear forces, and bending moments in a statically determinate structure.
| Equation | Description | Used to Determine (Examples) |
|---|---|---|
| $\sum F_x = 0$ | Sum of horizontal forces is zero. | Horizontal reactions, axial forces, horizontal shear forces. |
| $\sum F_y = 0$ | Sum of vertical forces is zero. | Vertical reactions, vertical shear forces. |
| $\sum M = 0$ | Sum of moments is zero. | Moment reactions, bending moments. |
It's important to note that the direct determination of all reactions and internal forces solely using static equilibrium equations is only possible for statically determinate structures. For statically indeterminate structures, there are more unknown reactions than available equilibrium equations. In such cases, additional methods are required, such as compatibility equations based on material properties and structural deformations (e.g., using the flexibility method, stiffness method, or slope-deflection method).
However, even in indeterminate structures, the static equilibrium equations are still valid and are used in conjunction with these other methods. The question specifically asks what "we may determine" by applying the static equations, and for determinate structures, all three quantities (reactions, shear, moment) are directly determinable.
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The forces whose line of action lie along the same line are known as:
The necessary condition of equilibrium of a body is-
The forces which meet at one point and have their line of action in different planes are called
If in a planar system, only 2 reaction forces are acting, then the system is:-