All Exams Test series for 1 year @ ₹349 only
Question

Value of determinant

\[ \begin{vmatrix} a - b & b - c & c - a \\ b - c & c - a & a - b \\ c - a & a - b & b - c \end{vmatrix} \] is:

The correct answer is

0

Evaluating the Value of the Given Determinant

We are asked to find the value of the determinant:

\( \Delta = \begin{vmatrix} a - b & b - c & c - a \\ b - c & c - a & a - b \\ c - a & a - b & b - c \end{vmatrix} \)

To evaluate this determinant, we can use properties of determinants. Let's consider applying column operations. Adding the second and third columns to the first column (operation \( C_1 \to C_1 + C_2 + C_3 \)) often simplifies determinants with this kind of cyclic pattern.

Let's perform the operation \( C_1 \to C_1 + C_2 + C_3 \). The new elements in the first column will be:

  • First row, first column: \( (a - b) + (b - c) + (c - a) = a - b + b - c + c - a = 0 \)
  • Second row, first column: \( (b - c) + (c - a) + (a - b) = b - c + c - a + a - b = 0 \)
  • Third row, first column: \( (c - a) + (a - b) + (b - c) = c - a + a - b + b - c = 0 \)

After applying the column operation, the determinant becomes:

\( \Delta = \begin{vmatrix} 0 & b - c & c - a \\ 0 & c - a & a - b \\ 0 & a - b & b - c \end{vmatrix} \)

A fundamental property of determinants states that if any column (or row) of a determinant consists entirely of zeros, then the value of the determinant is zero.

In this modified determinant, the first column consists entirely of zeros. Therefore, the value of the determinant is 0.

\( \Delta = 0 \)

This method using column operations is much simpler than expanding the determinant directly.

Revision Table: Key Determinant Properties

Property Description
Row/Column Swap Swapping two rows or two columns changes the sign of the determinant.
Scalar Multiplication Multiplying a row or column by a scalar \( k \) multiplies the determinant by \( k \).
Row/Column Addition Adding a multiple of one row (or column) to another row (or column) does not change the value of the determinant.
Zero Row/Column If a determinant has a row or column of all zeros, its value is 0.
Identical Rows/Columns If a determinant has two identical rows or columns, its value is 0.

Additional Information: Determinants and Cyclic Matrices

The given matrix has a specific structure where the elements in each row and column follow a cyclic pattern: \( (x, y, z) \), \( (y, z, x) \), \( (z, x, y) \), where \( x=a-b, y=b-c, z=c-a \). Notice that the sum of these elements is \( x+y+z = (a-b) + (b-c) + (c-a) = 0 \).

Matrices with this type of structure are related to circulant matrices. For the specific pattern where the sum of elements in the base sequence \( (x, y, z) \) is zero, the determinant will indeed be zero. This is because, as we showed, the sum of elements in each row (or column) is zero. Applying the operation \( R_1 \to R_1 + R_2 + R_3 \) (or \( C_1 \to C_1 + C_2 + C_3 \) as done in the solution) would result in a row (or column) of zeros, leading to a determinant of zero.

Was this answer helpful?

Similar Questions

  1. If \( B \) is a non-singular \( 4 \times 4 \) matrix and \( A \) is its adjoint such that \( |A| = 125 \), then \( |B| \) is:

  2. If \( A \) is a square matrix of order 3 such that \( |2 \operatorname{adj} A| = 288 \), then the value of \( |A| \) is:

  3. If \( A \operatorname{adj} A = \begin{bmatrix} -5 & 0 & 0 \\ 0 & -5 & 0 \\ 0 & 0 & -5 \end{bmatrix} \), then the value of \( |A| \) is:

  4. If \( A \) is a square matrix of order 3 and \( |A| = -3 \), then the value of \( |2AA^T| \) is:


Important Questions from Determinants

  1. If A is a square matrix of order 4 and |A|= 4, then |2A| will be:

  2. For a square matrix \( A_{n \times n} \):

    (A) \( |\text{adj} A| = |A|^{n-1} \)

    (B) \( |A| = |\text{adj} A|^{n-1} \)

    (C) \( A (\text{adj} A) = |A| I \)

    (D) \( |A^{-1}| = \frac{1}{|A|} \)

    Choose the correct answer from the options given below:

  3. Given the determinant:

    \[ \Delta = \begin{vmatrix} 1 & \cos x & 1 \\ -\cos x & 1 & \cos x \\ -1 & -\cos x & 1 \end{vmatrix} \]

    Which of the following statements are correct?

    (A) \( \Delta = 2(1 - \cos^2 x) \)

    (B) \( \Delta = 2(2 - \sin^2 x) \)

    (C) Minimum value of \( \Delta \) is 2

    (D) Maximum value of \( \Delta \) is 4

    Choose the correct answer from the options given below:

  4.  The angle between two lines whose direction ratios are proportional to \( (\sqrt{3} - 1) \), \( (-\sqrt{3} - 1) \), and -4 is:

  5. If \( B \) is a non-singular \( 4 \times 4 \) matrix and \( A \) is its adjoint such that \( |A| = 125 \), then \( |B| \) is:

Need Expert Advice?
Upcoming Exams
GATE
February 06, 2027
Test Series
CUET UG img
CUET
CUET UG 2026 Mock Test Series
963 Tests 9 Tests Free
20272 Attempts
4(792)
English

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App