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Question

Units of power is:

The correct answer is

Watt

Understanding the Units of Power

The question asks about the units used to measure power. Power is a fundamental concept in physics, representing the rate at which work is done or energy is transferred. It tells us how quickly energy is being used or converted.

The formula for power (\(P\)) is typically given by:

$$ P = \frac{W}{t} $$

Where:

  • \(W\) is the work done or energy transferred.
  • \(t\) is the time taken.

From this formula, we can determine the standard units of power based on the units of work (or energy) and time.

Identifying the SI Unit of Power

In the International System of Units (SI), the unit of work or energy is the Joule (\(J\)), and the unit of time is the second (\(s\)). Therefore, the SI unit of power is Joule per second (\(J/s\)).

This unit, Joule per second, is given a special name: the Watt (\(W\)). So, 1 Watt is equal to 1 Joule of work done or energy transferred per second.

$$ 1 \text{ Watt} = 1 \frac{\text{Joule}}{\text{second}} $$

The Watt is the standard SI unit of power.

Examining the Given Options

Let's look at the units provided in the options and determine which one represents power:

  • Joule: This is the SI unit of energy or work, not power.
  • Ohm: This is the SI unit of electrical resistance. It is denoted by the symbol \(\Omega\). Ohm's law relates Volt, Ampere, and Ohm (\(V = IR\)).
  • Watt: As discussed, this is the SI unit of power.
  • Volt: This is the SI unit of electric potential difference or voltage. It is denoted by the symbol \(V\).

Based on the definitions of these units, the unit of power is the Watt.

Summary of Units

Here is a brief summary of the units mentioned:

Unit Quantity SI Symbol
Joule Energy or Work \(J\)
Ohm Electrical Resistance \(\Omega\)
Watt Power \(W\)
Volt Electric Potential Difference \(V\)

Therefore, the correct unit for power among the given options is Watt.

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Important Questions from Power

  1. Which one of the following is the value of 1 KWh of energy converted into joules?

  2. Which of the following is correct regarding electric power?

  3. An elevator weighing 400 kg is to be lifted up at a constant velocity of 0.20 m/s. What would be the minimum horsepower of the motor to be used? (g = 9.8 m/s 2and there is no frictional loss)

  4. An elevator weighing 500 kg is to be lifted up at a constant velocity of 0.25 m/s. What would be the minimum horsepower of the motor to be used? G = 9.8 m/s2 and there is no frictional loss.

  5. One horse power is equal to

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