Units of power is:
Watt
The question asks about the units used to measure power. Power is a fundamental concept in physics, representing the rate at which work is done or energy is transferred. It tells us how quickly energy is being used or converted.
The formula for power (\(P\)) is typically given by:
$$ P = \frac{W}{t} $$
Where:
From this formula, we can determine the standard units of power based on the units of work (or energy) and time.
In the International System of Units (SI), the unit of work or energy is the Joule (\(J\)), and the unit of time is the second (\(s\)). Therefore, the SI unit of power is Joule per second (\(J/s\)).
This unit, Joule per second, is given a special name: the Watt (\(W\)). So, 1 Watt is equal to 1 Joule of work done or energy transferred per second.
$$ 1 \text{ Watt} = 1 \frac{\text{Joule}}{\text{second}} $$
The Watt is the standard SI unit of power.
Let's look at the units provided in the options and determine which one represents power:
Based on the definitions of these units, the unit of power is the Watt.
Here is a brief summary of the units mentioned:
| Unit | Quantity | SI Symbol |
|---|---|---|
| Joule | Energy or Work | \(J\) |
| Ohm | Electrical Resistance | \(\Omega\) |
| Watt | Power | \(W\) |
| Volt | Electric Potential Difference | \(V\) |
Therefore, the correct unit for power among the given options is Watt.
Which one of the following is the value of 1 KWh of energy converted into joules?
Which of the following is correct regarding electric power?
An elevator weighing 400 kg is to be lifted up at a constant velocity of 0.20 m/s. What would be the minimum horsepower of the motor to be used? (g = 9.8 m/s 2and there is no frictional loss)
An elevator weighing 500 kg is to be lifted up at a constant velocity of 0.25 m/s. What would be the minimum horsepower of the motor to be used? G = 9.8 m/s2 and there is no frictional loss.
One horse power is equal to