Under what condition will the lines m2x + ny - 1 = 0 and n2x - my + 2 = 0 be perpendicular?
mn - 1 = 0
For the lines to be perpendicular, the condition is mn - 1 = 0.
A line through \((1, -1, 2)\) with direction ratios \(<3, 2, 2>\) meets the plane \(x + 2y + 3z = 18\). What is the point of intersection of line and plane?
ABC is an equilateral triangle and AD is the altitude on BC. If the coordinates of A are (1, 2) and that of D are (-2, 6), then what is the equation of BC?