This problem involves calculating the time when two trains moving towards each other will meet. We need to account for their different starting times and speeds.
Train A starts at 7 a.m. and Train B starts at 8 a.m. In the one hour between 7 a.m. and 8 a.m., Train A travels a certain distance.
At 8 a.m., when Train B starts, the distance between the two trains is reduced.
Now, we calculate the time it takes for the trains to cover the remaining distance at their relative speed.
Convert the time into hours and minutes:
The trains will meet 2 hours and 20 minutes after 8 a.m.
The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?
The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is:
A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?
A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?