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Question

Twenty-one litres of water in a tank is to be divided into three equal parts using only 5, 8 and 12 litre capacity cans. The minimum number of transfers needed to achieve this is

The correct answer is
7

Solving the Water Division Problem

The objective is to divide a total volume of 21 litres of water into three equal parts, each measuring 7 litres.

The available tools are cans with capacities of 5 litres, 8 litres, and 12 litres.

Key Cans and Calculation

The problem requires measuring exactly 7 litres. A useful relationship using the available cans is:

$12 \text{ L} - 5 \text{ L} = 7 \text{ L}$

This relationship is crucial for finding a way to isolate 7 litres.

Minimum Transfers Analysis

By executing a specific sequence of pouring operations using the 5L, 8L, and 12L cans, it is possible to divide the 21 litres into three separate 7-litre portions. The minimum number of transfers needed to accomplish this task is 7.

This minimum is achieved through a calculated series of pours, effectively measuring and separating the water into the desired equal parts.

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Important Questions from Puzzle (Notes)

  1. Four individuals - P, Q, R and S - are suspects in a theft case. They make the following statements :
    P says: "Q is guilty."
    Q says: "R is guilty."
    R says: "P is innocent."
    S says: "I am innocent"
    If it is known that exactly one of them is guilty, and only the guilty person lies (all innocent people tell the truth), then who is the guilty one?
  2. In which company, C's interview was scheduled?
  3. Who went to Nagpur?
  4. What is the sum of the digits of the number Q?
  5. What is the sum of A and Q if A is smaller than B?
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