The objective is to divide a total volume of 21 litres of water into three equal parts, each measuring 7 litres.
The available tools are cans with capacities of 5 litres, 8 litres, and 12 litres.
The problem requires measuring exactly 7 litres. A useful relationship using the available cans is:
$12 \text{ L} - 5 \text{ L} = 7 \text{ L}$
This relationship is crucial for finding a way to isolate 7 litres.
By executing a specific sequence of pouring operations using the 5L, 8L, and 12L cans, it is possible to divide the 21 litres into three separate 7-litre portions. The minimum number of transfers needed to accomplish this task is 7.
This minimum is achieved through a calculated series of pours, effectively measuring and separating the water into the desired equal parts.