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Question

Tim was calculating the area of a square. He made a mistake in measuring the side of the square, the error being 10% in excess. Find the resultant percentage error in the area of the square.

The correct answer is

21%

To solve the problem of finding the resultant percentage error in the area of a square when its side length is measured with a 10% excess error, follow these steps:

The side of the square is originally measured to be s. With a 10% increase in measurement, the side length becomes s + 0.1s = 1.1s.

To find the change in the area:

The original area A_o of the square is given by:
A_o = s²

The new area A_n with the increased side is:
A_n = (1.1s)² = 1.21s²

Now, calculate the change in area:
Change in area = New area - Original area
= 1.21s² - s² = 0.21s²

The percentage error in the area is given by:
\[ \text{Percentage Error} = \left(\frac{\text{Change in Area}}{\text{Original Area}}\right) \times 100\% \]

\[ = \left(\frac{0.21s²}{s²}\right) \times 100\% \]
= \[ 0.21 \times 100\% = 21\%\]

Therefore, the resultant percentage error in the area of the square is 21%.
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