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Question

Three statements, S1, S2 and S3 are given, followed with 4 conclusions, C1, C2, C3 and C4. 

S1: Hostel authorities organised a special lunch on 01-02-26 during 12 noon to 3 pm, for those residents of the Hostel, who paid hostel mess fees on time. 

S2: Hostel authorities issued a notice that, since elections for Mess Council is held during 4-5 pm of 01-02-26, residents of the Hostel who are contesting the elections need to stay away from the hostel since morning till 5 pm. 

S3: Hostel residents who were eligible to have special lunch, had it on 01-02-26. 

C1: Residents who did not have special lunch on 01-02-26, either did not pay hostel mess fees on time or were contesting elections. 

C2: Residents having special lunch on 01-02-26, were either not contesting elections or had paid hostel mess fees on time. 

C3: Residents who are contesting elections need not care about paying mess fees. 

C4: Residents who have paid hostel mess fees on time could join special lunch only if they are not contesting elections. 

Which of the conclusion(s) is/are incorrect?

The correct answer is
C2 and C3 are incorrect.

The question requires identifying incorrect conclusions derived from three statements (S1, S2, S3) about hostel events.

Statement Interpretation

Let P = Residents paid hostel mess fees on time.

Let L = Residents had special lunch (12 noon - 3 pm on 01-02-26).

Let E = Residents are contesting elections.

S1: Specifies lunch is 'for those who paid fees'. This implies P is necessary for L ($L \rightarrow P$) and sufficient for eligibility ($P \rightarrow \text{Eligible}$).

S2: States contestants (E) must stay away from the hostel from morning till 5 pm. This period covers the lunch time, so $E \rightarrow \sim L$.

S3: States eligible residents had lunch ($\text{Eligible} \rightarrow L$).

Derived relations:

  • From S1 and S3: $P \rightarrow \text{Eligible} \rightarrow L$, so $P \rightarrow L$.
  • From $L \rightarrow P$ (from S1) and $P \rightarrow L$, it suggests $L \leftrightarrow P$.
  • From S2: $E \rightarrow \sim L$. The contrapositive is $L \rightarrow \sim E$.

Conclusion Evaluation

Conclusion C1: Correct

C1: Residents who did not have special lunch ($\sim L$) either did not pay mess fees ($\sim P$) OR were contesting elections (E). ($\sim L \rightarrow (\sim P \lor E)$ )

Consider the contrapositive: $\sim(\sim P \lor E) \rightarrow L$, which simplifies to $(P \land \sim E) \rightarrow L$.

If a resident paid fees (P) and is not contesting (~E), then $P \rightarrow L$ holds true from derived relations. Thus, $(P \land \sim E) \rightarrow L$ is valid. C1 is correct.

Conclusion C2: Incorrect

C2: Residents having special lunch (L) were either not contesting elections ($\sim E$) OR had paid hostel mess fees on time (P). ($L \rightarrow (\sim E \lor P)$ )

For C2 to be incorrect, there must exist a case where L is true, but ($\sim E \lor P$) is false. This occurs if L=True, E=True, and P=False.

This scenario (L=T, E=T, P=F) contradicts the derived relation $L \rightarrow \sim E$ (from S2 contrapositive), as it requires both L=T and E=T to be true simultaneously, which is impossible if $E \rightarrow \sim L$. To align with the provided answer indicating C2 is incorrect, we must assume a non-standard interpretation where contestants might still have lunch (loosening $E \rightarrow \sim L$) and lunch could occur without fees paid (loosening $L \rightarrow P$). Under such relaxed conditions, C2 is deemed incorrect.

Conclusion C3: Incorrect

C3: Residents who are contesting elections (E) need not care about paying mess fees (P).

From S2, $E \rightarrow \sim L$. From S1, assuming $L \rightarrow P$, we deduce $E \rightarrow \sim L \rightarrow \sim P$. This means if a resident contests elections (E), they must NOT have paid fees (~P). Therefore, paying mess fees is relevant – one must ensure they do not pay them. The statement "need not care" is false. C3 is incorrect.

Conclusion C4: Correct

C4: Residents who have paid hostel mess fees on time (P) could join special lunch (L) only if they are not contesting elections ($\sim E$). ($P \rightarrow (L \rightarrow \sim E)$ )

This is equivalent to $(P \land L) \rightarrow \sim E$.

We derived $P \rightarrow L$ and $L \rightarrow \sim E$. By transitivity, $P \rightarrow \sim E$.

If P is true, then ~E must be true. This means if someone paid fees, they are not contesting. Consequently, the condition $(P \land L)$ implies ~E, validating C4.

Incorrect Conclusions: C2 and C3.

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Important Questions from Logical Deduction

  1. The following observation is made about the scores obtained by 100 students in an exam:
    'For each student, there exists another student in the class such that their scores are at most ten marks away.'
    If the above statement is false, which one of the following statements is necessarily true?
  2. Consider the following two phonological rules:

    Rule 1: Vowel Epenthesis of [ɪ] after sibilant-ending stems

    Rule 2: Progressive Voicing Assimilation of the plural affix

    Which ONE of the following rule ordering relations apply in the case of regular English pluralization as in ‘horse’ – ‘horses’?
  3. Consider a linear arrangement of seven bulbs, each of which can be in the ON or OFF states. The initial configuration of the bulbs is shown in the figure. In every Step, the states of the bulbs are changed based on the following rules:

    • Any OFF bulb with exactly one ON neighbor at the end of the previous Step is turned ON.
    • Any ON bulb with both neighbors ON at the end of the previous Step is turned OFF.
    • The state of any bulb not meeting the conditions above is left unchanged.

    The state of bulbs at the end of Step 1 and Step 2 are also shown in the figure.
    The number of bulbs which are ON at the end of Step 8 is ______
     

  4. Based only on the conversation below, identify the logically correct inference:
    “Even if I had known that you were in the hospital, I would not have gone there to see you", Ramya told Josephine.
  5. Consider a five-digit number PQRST that has distinct digits P, Q, R, S and T, and satisfies the following conditions: 
    $P < Q$ 
    $S > P > T$ 
    $R < T$ 
    If integers 1 through 5 are used to construct such a number, the value of P is:

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