We are given three numbers that are in the ratio 5:1:7. We are also given their Least Common Multiple (LCM), which is 7595. The goal is to find the Highest Common Factor (HCF) of these three numbers.
Let the three numbers be represented using the given ratio and a common factor, which is the HCF. Let the HCF be represented by '$x$'.
The LCM of numbers represented as $ax$, $bx$, and $cx$ (where $x$ is the HCF) can be calculated as:
LCM = $x \times \text{LCM}(a, b, c)$
In this case, $a=5$, $b=1$, and $c=7$. So, we need to find the LCM of 5, 1, and 7.
Since 5, 1, and 7 are coprime numbers (their only common factor is 1), their LCM is simply their product:
LCM(5, 1, 7) = $5 \times 1 \times 7 = 35$
Now, we can express the LCM of the three numbers (5x, x, 7x) in terms of $x$:
LCM(5x, x, 7x) = $x \times \text{LCM}(5, 1, 7) = x \times 35 = 35x$
We are given that the LCM of the three numbers is 7595. We have calculated the LCM as $35x$. Therefore, we can set up the equation:
$$35x = 7595$$
To find the HCF ($x$), we need to solve this equation for $x$:
$$x = \frac{7595}{35}$$
Let's perform the division:
So, the value of $x$ is 217.
Since $x$ represents the Highest Common Factor (HCF) of the three numbers, the HCF is 217.
The three numbers are:
The HCF of 1085, 217, and 1519 is indeed 217.
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?