Three men can complete a work in 6 days and five women can complete the same work in 18 days. In how many days can 4 men and 10 women together complete the same work?
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This problem involves calculating the time taken by a group of men and women working together to complete a task, given the time taken by individual groups of men and women.
To solve this, we first need to determine the individual work rate of one man and one woman per day. The work rate is the fraction of the total work completed in one day.
We are given that:
Let the total work be 1 unit.
3 men complete the work in 6 days.
Work done by 3 men in 1 day is $\frac{1}{6}$ of the total work.
Therefore, the work done by 1 man in 1 day is $\frac{1}{6} \times \frac{1}{3} = \frac{1}{18}$ of the total work.
So, 1 man's 1-day work rate is $\frac{1}{18}$.
5 women complete the work in 18 days.
Work done by 5 women in 1 day is $\frac{1}{18}$ of the total work.
Therefore, the work done by 1 woman in 1 day is $\frac{1}{18} \times \frac{1}{5} = \frac{1}{90}$ of the total work.
So, 1 woman's 1-day work rate is $\frac{1}{90}$.
We need to find how many days 4 men and 10 women together can complete the same work. First, let's find their combined work rate per day.
Work done by 4 men in 1 day = $4 \times (\text{1 man's 1-day work rate}) = 4 \times \frac{1}{18} = \frac{4}{18} = \frac{2}{9}$ of the work.
Work done by 10 women in 1 day = $10 \times (\text{1 woman's 1-day work rate}) = 10 \times \frac{1}{90} = \frac{10}{90} = \frac{1}{9}$ of the work.
Combined work done by 4 men and 10 women in 1 day = (Work by 4 men in 1 day) + (Work by 10 women in 1 day)
Combined work rate per day = $\frac{2}{9} + \frac{1}{9} = \frac{2+1}{9} = \frac{3}{9} = \frac{1}{3}$ of the work.
So, 4 men and 10 women together complete $\frac{1}{3}$ of the work in 1 day.
If 4 men and 10 women complete $\frac{1}{3}$ of the work in 1 day, the total number of days required to complete the entire work (which is 1 unit of work) is the reciprocal of their combined daily work rate.
Total days = $\frac{\text{Total Work}}{\text{Combined Work Rate per Day}} = \frac{1}{\frac{1}{3}} = 1 \times 3 = 3$ days.
Therefore, 4 men and 10 women together can complete the work in 3 days.
| Group | Time to Complete Work (Days) | Total Work Units (in 1 day) | Work Rate per Person per Day |
|---|---|---|---|
| 3 Men | 6 | $\frac{1}{6}$ | $\frac{1}{6} \times \frac{1}{3} = \frac{1}{18}$ (for 1 man) |
| 5 Women | 18 | $\frac{1}{18}$ | $\frac{1}{18} \times \frac{1}{5} = \frac{1}{90}$ (for 1 woman) |
| 4 Men | - | $4 \times \frac{1}{18} = \frac{2}{9}$ | - |
| 10 Women | - | $10 \times \frac{1}{90} = \frac{1}{9}$ | - |
| 4 Men + 10 Women | ? | $\frac{2}{9} + \frac{1}{9} = \frac{3}{9} = \frac{1}{3}$ | - |
Time taken by 4 men and 10 women = $\frac{1}{\text{Combined daily work rate}} = \frac{1}{\frac{1}{3}} = 3$ days.
| Concept | Explanation | Formula/Relation |
|---|---|---|
| Work Rate | The amount of work done per unit of time (e.g., per day). | Work Rate = $\frac{\text{Total Work}}{\text{Time Taken}}$ |
| Time Taken | The total time required to complete a task. | Time Taken = $\frac{\text{Total Work}}{\text{Work Rate}}$ |
| Total Work | The entire task to be completed (often considered as 1 unit). | Total Work = Work Rate $\times$ Time Taken |
| Combined Work Rate | The sum of individual work rates when multiple people or entities work together. | Combined Rate = Rate$_1$ + Rate$_2$ + ... |
Work and time problems often involve different scenarios:
Understanding the concept of work rate as the reciprocal of the time taken is fundamental to solving these problems. If someone completes a work in 'N' days, their 1-day work rate is $\frac{1}{N}$. When people work together, their daily work rates add up.
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