(Left) 267 513 671 895 729 (Right)
(Example: 697 - First digit = 6, second digit = 9 and third digit = 7)
(NOTE: All operations to be done from left to right.)
If the digits of each number are added and their respective resultants are arranged in the ascending order, what is the number placed 4th from the right end?
We are given five 3-digit numbers: 267, 513, 671, 895, and 729. The task is to perform two main operations:
The note clarifies that operations within a number are done from left to right, which is the standard way to sum digits.
Let's calculate the sum of digits for each given 3-digit number:
| Number | Calculation (Left to Right) | Sum of Digits |
|---|---|---|
| 267 | $2 + 6 + 7$ | 15 |
| 513 | $5 + 1 + 3$ | 9 |
| 671 | $6 + 7 + 1$ | 14 |
| 895 | $8 + 9 + 5$ | 22 |
| 729 | $7 + 2 + 9$ | 18 |
The sums we obtained are 15, 9, 14, 22, and 18. Now, we need to arrange these results in ascending order (from smallest to largest):
The ascending order is: 9, 14, 15, 18, 22.
We look at the ordered list of sums: 9, 14, 15, 18, 22.
Let's count from the right end:
Therefore, the number placed 4th from the right end in the ascending list of digit sums is 14.
Refer to the following number and symbol series and answer the question that follows.
All numbers are single-digits. Counting to be done from left to right only.
(Left) & 1 # 6 * ^ @ 3 & $ 7 Ω $ 2 # 6 @ 2 % 9 (Right)
If all the symbols are dropped from the series, which of the following will be third from the left?