This problem requires us to modify a given number based on whether its digits are even or odd, and then perform a specific calculation on the resulting number. Let's break down the process step-by-step.
We are given the number $7145362$. The rules for transformation are:
We need to apply these rules to each digit of the number $7145362$.
Let's identify each digit, its type (odd or even), and the result after applying the rule:
| Original Digit | Type | Operation | New Digit |
|---|---|---|---|
| 7 | Odd | $7 + 2$ | 9 |
| 1 | Odd | $1 + 2$ | 3 |
| 4 | Even | $4 + 2$ | 6 |
| 5 | Odd | $5 + 2$ | 7 |
| 3 | Odd | $3 + 2$ | 5 |
| 6 | Even | $6 + 2$ | 8 |
| 2 | Even | $2 + 2$ | 4 |
By replacing the original digits with the new digits in the same order, we form the new number. The original number was $7145362$. The transformed digits are $9, 3, 6, 7, 5, 8, 4$.
Therefore, the new number formed is $9367584$.
The question asks for the sum of the last two and first two digits in the new number.
Now, we calculate the sum:
Sum = (First two digits sum) + (Last two digits sum)
Sum = $ (9 + 3) + (8 + 4) $
Sum = $ 12 + 12 $
Sum = $ 24 $
The calculated sum is $24$. This matches one of the options provided.
Refer to the following number and symbol series and answer the question that follows.
All numbers are single-digits. Counting to be done from left to right only.
(Left) & 1 # 6 * ^ @ 3 & $ 7 Ω $ 2 # 6 @ 2 % 9 (Right)
If all the symbols are dropped from the series, which of the following will be third from the left?