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Question

There is a rectangular garden of 220 metres × 70 metres. A path of width 4 metres is built around the garden. What is the area of the path?

The correct answer is

2384 metre2

Understanding the Problem: Rectangular Garden and Path Area

The problem asks us to calculate the area of a path built around a rectangular garden. We are given the dimensions of the garden and the uniform width of the path surrounding it.

Given Information:

  • Garden Length: 220 metres
  • Garden Width: 70 metres
  • Path Width: 4 metres

The path is built around the garden. This means the path forms a larger rectangle outside the garden. To find the area of the path, we need to find the area of the larger rectangle (garden plus path) and subtract the area of the inner rectangle (the garden itself).

Step-by-Step Calculation of the Path Area

Step 1: Calculate the Area of the Garden

The garden is a rectangle. The area of a rectangle is given by the formula: Area = Length × Width.

Area of Garden = Garden Length × Garden Width

\(\text{Area}_{\text{garden}} = 220 \text{ m} \times 70 \text{ m}\)

\(\text{Area}_{\text{garden}} = 15400 \text{ m}^2\)

Step 2: Calculate the Dimensions of the Garden Including the Path

Since the path of width 4 metres is built all around the garden, it adds 4 metres to each end of both the length and the width.

  • New Length (including path) = Garden Length + 2 × Path Width
  • New Width (including path) = Garden Width + 2 × Path Width

New Length = 220 m + 2 \(\times\) 4 m

New Length = 220 m + 8 m

New Length = 228 m

New Width = 70 m + 2 \(\times\) 4 m

New Width = 70 m + 8 m

New Width = 78 m

Step 3: Calculate the Area of the Garden Including the Path

This larger area is also a rectangle with the new calculated dimensions.

Area (Garden + Path) = New Length × New Width

\(\text{Area}_{\text{total}} = 228 \text{ m} \times 78 \text{ m}\)

To calculate \(228 \times 78\):

200 20 8
70 14000 1400 560
8 1600 160 64

Summing the values: \(14000 + 1400 + 560 + 1600 + 160 + 64 = 17784\)

\(\text{Area}_{\text{total}} = 17784 \text{ m}^2\)

Step 4: Calculate the Area of the Path

The area of the path is the difference between the total area (garden plus path) and the area of the garden alone.

Area of Path = Area (Garden + Path) - Area of Garden

\(\text{Area}_{\text{path}} = \text{Area}_{\text{total}} - \text{Area}_{\text{garden}}\)

\(\text{Area}_{\text{path}} = 17784 \text{ m}^2 - 15400 \text{ m}^2\)

\(\text{Area}_{\text{path}} = 2384 \text{ m}^2\)

Conclusion

The area of the path built around the rectangular garden is 2384 square metres.

Revision Table: Rectangular Area Calculations

Component Length Width Area
Garden 220 m 70 m \(220 \times 70 = 15400\) m<sup>2</sup>
Garden + Path \(220 + 2 \times 4 = 228\) m \(70 + 2 \times 4 = 78\) m \(228 \times 78 = 17784\) m<sup>2</sup>
Path Only N/A N/A \(17784 - 15400 = 2384\) m<sup>2</sup>

Additional Information: Areas of Rectangular Shapes

Calculating areas involving paths around rectangular shapes is a common geometry problem. The key idea is to consider the shapes as nested rectangles. The area of the path is the area of the outer rectangle minus the area of the inner rectangle.

  • When a path is *outside* a rectangle, both the length and width of the outer rectangle are increased by twice the path width.
  • When a path is *inside* a rectangle, both the length and width of the inner rectangle are decreased by twice the path width. The area of the path would then be the area of the outer rectangle minus the area of the inner rectangle.

Understanding how the path width affects the overall dimensions is crucial for accurately calculating the areas.

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Important Questions from Plane Figures

  1. If the area of a square is 625 cm 2, then what is the perimeter of the square?

  2. The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?

  3. One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.

  4. The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:

  5. The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).

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