There is a metric space (E, d) such that every Cauchy sequence in (E, d) is convergent, then the metric space is
complete
Let's break down the concepts involved in this question about metric spaces and sequences.
A metric space is a set where a distance (or metric) is defined between any two points. We denote a metric space as \( (E, d) \), where \( E \) is the set and \( d \) is the metric function.
Inside a metric space, we can talk about sequences of points.
An important property is that every convergent sequence is a Cauchy sequence. However, the converse is not always true in any arbitrary metric space.
The question describes a metric space \( (E, d) \) where every Cauchy sequence in \( (E, d) \) is convergent. This specific property is the definition of a complete metric space.
So, if in a metric space \( (E, d) \), it is guaranteed that every Cauchy sequence converges to a point within the space \( E \), then the space is called a complete metric space.
Let's look at the given options:
Therefore, a metric space \( (E, d) \) in which every Cauchy sequence converges is by definition a complete metric space.
This property of being a complete metric space is crucial in many areas of mathematics, especially analysis, as it ensures that limits of Cauchy sequences exist within the space, which is important for defining concepts like continuity and integration.
Which statement states that "Every complete metric space is of second category"?
Let (X, d) be a metric space then what can you say about X and d?
Which of the following metric space is not complete?
Let (X, d) be a metric sparse and let B be a subset of X then if B is closed then B is also ______.
Let (X, d) be a metric space and Pn be the Cauchy sequence defined then {Pn} is ______.