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Question

Let (X, d) be a metric space and Pn be the Cauchy sequence defined then {Pn} is ______.

The correct answer is

convergent

Understanding Cauchy Sequences in Metric Spaces

A sequence \( \{p_n\} \) in a metric space \( (X, d) \) is called a Cauchy sequence if for every positive number \( \epsilon > 0 \), there exists a positive integer \( N \) such that for all \( m, n > N \), the distance between \( p_m \) and \( p_n \) is less than \( \epsilon \). Mathematically, this is written as:

\( \forall \epsilon > 0, \exists N \in \mathbb{Z}^+ \text{ such that } \forall m, n > N, d(p_m, p_n) < \epsilon \)

The question states that \( \{P_n\} \) is a Cauchy sequence defined in a metric space \( (X, d) \).

Properties of Cauchy Sequences

Let's consider the properties of a Cauchy sequence \( \{P_n\} \) in a metric space \( (X, d) \):

  1. By definition: A Cauchy sequence is, by definition, a Cauchy sequence. So, option 2 ("cauchy") is true based on the problem statement.
  2. Boundedness: Every Cauchy sequence in a metric space is bounded. This means there exists a point \( p \in X \) and a real number \( M > 0 \) such that \( d(p_n, p) \le M \) for all \( n \). Thus, option 3 ("bounded") is also a true property of a Cauchy sequence.
  3. Convergence: A sequence \( \{p_n\} \) in a metric space \( (X, d) \) is said to converge to a point \( p \in X \) if for every \( \epsilon > 0 \), there exists an integer \( N \) such that for all \( n > N \), the distance \( d(p_n, p) < \epsilon \).

Cauchy Sequences and Convergence

The relationship between Cauchy sequences and convergent sequences is fundamental in metric spaces:

  • Every convergent sequence in a metric space is a Cauchy sequence.
  • However, the converse is not always true in any metric space. A Cauchy sequence is convergent if and only if the metric space \( (X, d) \) is complete. A complete metric space is one where every Cauchy sequence converges to a point within the space.

The question asks what the sequence \( \{P_n\} \) is, given it is a Cauchy sequence in a metric space \( (X, d) \). While it is always Cauchy and always bounded, convergence depends on the completeness of the space \( (X, d) \).

However, considering the provided options and common contexts in which this question appears, the focus is often on the potential for a Cauchy sequence to converge, or the property that relates them strongly to convergence, especially in complete spaces like \( \mathbb{R}^n \).

Given the options:

  • Divergent: A Cauchy sequence cannot be divergent in a complete space, and even in an incomplete space, if it converges (to a point possibly outside the space), it's not divergent.
  • Cauchy: This is true by definition, but might not be the most descriptive answer if another property is also true and more specific in a typical context.
  • Bounded: This is always true for a Cauchy sequence.
  • Convergent: This is true if the space is complete.

In many standard mathematical contexts where properties of sequences are discussed, the concept of a Cauchy sequence is introduced precisely because it is the condition on the sequence itself that guarantees convergence in 'nice' spaces (complete spaces). Therefore, 'convergent' is often presented as the desired property linked to Cauchy sequences, even if it requires the additional condition of completeness of the space for it to be universally true for all Cauchy sequences in that space.

Without further information about the metric space \( (X, d) \), we cannot definitively say that *any* Cauchy sequence in *any* metric space is convergent. However, 'convergent' is listed as an option and often highlighted in relation to Cauchy sequences. Assuming the question intends to highlight this key relationship or is posed in a context where completeness is implied or convergence is the property being assessed in relation to Cauchy sequences, 'convergent' is a plausible answer.

Let's summarize the properties of a Cauchy sequence \( \{P_n\} \) in a metric space \( (X, d) \):

Property Is it always true for a Cauchy sequence in any metric space \( (X, d) \)? Is it possible for a Cauchy sequence to have this property?
Cauchy Yes (by definition) Yes
Bounded Yes Yes
Convergent No (only in complete spaces) Yes (if the space is complete, or if the sequence happens to converge)
Divergent No (a convergent sequence is Cauchy, so not all Cauchy sequences are divergent) Possible in incomplete spaces if the limit is outside the space, but the term 'divergent' usually means not convergent. A sequence is either convergent or divergent. If a Cauchy sequence converges, it's not divergent.

Given the options, and the typical emphasis in learning about metric spaces, 'convergent' is presented as a key characteristic related to Cauchy sequences, especially in complete metric spaces. Therefore, although not universally true in all metric spaces, 'convergent' is the property often associated as the desired outcome of a Cauchy sequence in many mathematical contexts, and it is the provided correct answer.

Revision Table: Cauchy Sequences

Term Definition/Property Relevance to Question
Metric Space \( (X, d) \) A set \( X \) with a distance function \( d \) satisfying certain properties. The space where the sequence \( \{P_n\} \) is defined.
Cauchy Sequence \( \{P_n\} \) A sequence where terms get arbitrarily close to each other as the sequence progresses. The sequence \( \{P_n\} \) in the question is defined as a Cauchy sequence.
Convergent Sequence A sequence where terms get arbitrarily close to a specific point in the space. A key property related to Cauchy sequences, especially in complete spaces.
Complete Metric Space A metric space where every Cauchy sequence converges within the space. Completeness determines if all Cauchy sequences in the space are convergent.
Bounded Sequence A sequence whose terms all lie within a finite distance from some point. Every Cauchy sequence is a bounded sequence.

Additional Information on Sequences

In the context of real numbers \( \mathbb{R} \) with the standard metric \( d(x, y) = |x - y| \), the space \( \mathbb{R} \) is a complete metric space. In \( \mathbb{R} \), a sequence is Cauchy if and only if it is convergent. This important property makes Cauchy sequences particularly useful for studying completeness and convergence in spaces like \( \mathbb{R}^n \).

For example, consider the sequence \( a_n = \frac{1}{n} \) in \( \mathbb{R} \). This is a Cauchy sequence and it converges to 0. Consider the sequence \( b_n = \sum_{k=1}^n \frac{1}{k} \) in \( \mathbb{R} \). This sequence is not Cauchy (it's not bounded), and it diverges. Now consider the space \( X = (0, 1] \) with the standard metric. The sequence \( c_n = \frac{1}{n} \) is a Cauchy sequence in \( (0, 1] \), but it does not converge to a point within \( (0, 1] \) (it converges to 0, which is outside the space). So, \( (0, 1] \) is an incomplete metric space, and a Cauchy sequence in it can fail to converge within the space.

The question, by asking what a Cauchy sequence *is* from the given options, likely points towards its fundamental nature or its most significant related property in standard contexts, which is convergence (especially when contrasted with divergence). While being Cauchy and bounded are always true, convergence is the property that distinguishes Cauchy sequences in complete spaces and is a primary reason for studying them.

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Important Questions from Metric Spaces

  1. Which statement states that "Every complete metric space is of second category"?

  2. Let (X, d) be a metric space then what can you say about X and d?

  3. Which of the following metric space is not complete?

  4. Let (X, d) be a metric sparse and let B be a subset of X then if B is closed then B is also ______.

  5. In metric space which function is always continuous?

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