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Question

There are two candidates P and Q in an election. During the campaign, 40% of the voters promised to vote for P, and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose, P lost by 2 votes, then what was the total number of voters?

The correct answer is

100

Understanding the Election Scenario

This problem involves calculating the total number of voters in an election based on initial promises made by voters to candidates P and Q, and subsequent changes in their voting intentions. We are given that candidate P lost the election by 2 votes.

Step-by-Step Calculation of Total Voters

Let's denote the total number of voters as $N$.

Initial Voter Promises:

  • Percentage of voters promised to vote for P: 40%
  • Percentage of voters promised to vote for Q: The rest, which is $100\% - 40\% = 60\%$

Changes in Voting Intentions:

  • Voters who promised P but switched to Q: 15% of those who promised P.
  • Voters who promised Q but switched to P: 25% of those who promised Q.

Calculating Actual Votes for P and Q:

Let's calculate the number of voters switching:

  • Number of voters switching from P to Q = $15\%$ of $40\%$ of $N$ $= 0.15 \times (0.40 \times N)$ $= 0.06 \times N$
  • Number of voters switching from Q to P = $25\%$ of $60\%$ of $N$ $= 0.25 \times (0.60 \times N)$ $= 0.15 \times N$

Now, let's find the final actual votes for each candidate:

  • Actual Votes for P = (Voters initially promised to P) - (Voters who switched from P to Q) + (Voters who switched from Q to P) Actual Votes for P = $(0.40 \times N) - (0.06 \times N) + (0.15 \times N)$ Actual Votes for P = $(0.40 - 0.06 + 0.15) \times N$ Actual Votes for P = $0.49 \times N$
  • Actual Votes for Q = (Voters initially promised to Q) - (Voters who switched from Q to P) + (Voters who switched from P to Q) Actual Votes for Q = $(0.60 \times N) - (0.15 \times N) + (0.06 \times N)$ Actual Votes for Q = $(0.60 - 0.15 + 0.06) \times N$ Actual Votes for Q = $0.51 \times N$

Using the Election Outcome to Find Total Voters:

We are given that P lost the election by 2 votes. This means the number of votes for P is 2 less than the number of votes for Q.

Mathematically, this can be written as:

Actual Votes for P = Actual Votes for Q - 2

Substituting the expressions we found:

$0.49 \times N = (0.51 \times N) - 2$

Now, we solve for $N$:

$2 = (0.51 \times N) - (0.49 \times N)$

$2 = (0.51 - 0.49) \times N$

$2 = 0.02 \times N$

$N = \frac{2}{0.02}$

$N = \frac{200}{2}$

$N = 100$

Summary of Votes:

Candidate Initial Promise Switched Away Switched To Actual Votes
P $0.40N$ $0.06N$ (to Q) $0.15N$ (from Q) $0.49N$
Q $0.60N$ $0.15N$ (to P) $0.06N$ (from P) $0.51N$

With $N=100$:

  • Actual Votes for P = $0.49 \times 100 = 49$
  • Actual Votes for Q = $0.51 \times 100 = 51$

The difference is $51 - 49 = 2$ votes, which matches the condition that P lost by 2 votes.

Conclusion

The total number of voters was 100.

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Important Questions from Percentage

  1. Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;

  2. The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:

  3. The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.

  4. The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:

  5. The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is:

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