There are two candidates P and Q in an election. During the campaign, 40% of the voters promised to vote for P, and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose, P lost by 2 votes, then what was the total number of voters?
100
This problem involves calculating the total number of voters in an election based on initial promises made by voters to candidates P and Q, and subsequent changes in their voting intentions. We are given that candidate P lost the election by 2 votes.
Let's denote the total number of voters as $N$.
Let's calculate the number of voters switching:
Now, let's find the final actual votes for each candidate:
We are given that P lost the election by 2 votes. This means the number of votes for P is 2 less than the number of votes for Q.
Mathematically, this can be written as:
Actual Votes for P = Actual Votes for Q - 2
Substituting the expressions we found:
$0.49 \times N = (0.51 \times N) - 2$
Now, we solve for $N$:
$2 = (0.51 \times N) - (0.49 \times N)$
$2 = (0.51 - 0.49) \times N$
$2 = 0.02 \times N$
$N = \frac{2}{0.02}$
$N = \frac{200}{2}$
$N = 100$
| Candidate | Initial Promise | Switched Away | Switched To | Actual Votes |
| P | $0.40N$ | $0.06N$ (to Q) | $0.15N$ (from Q) | $0.49N$ |
| Q | $0.60N$ | $0.15N$ (to P) | $0.06N$ (from P) | $0.51N$ |
With $N=100$:
The difference is $51 - 49 = 2$ votes, which matches the condition that P lost by 2 votes.
The total number of voters was 100.
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