What is the probability that the opposite side is the same colour as the one side we observed ?
We have three distinct cards:
A card is chosen randomly, and one side is observed. We need to find the probability that the side facing down (the opposite side) is the same color as the side we observed.
Let's consider all possible equally likely outcomes based on the side we observe. There are 6 sides in total across the three cards, and any of these could be the one we observe.
We list each possible observation and check if the opposite side matches the observed color:
To calculate the probability, we consider each of the 6 sides as a potential observation.
Total number of equally likely observable sides = 2 (from BB) + 2 (from RR) + 2 (from BR) = 6.
Number of favorable outcomes (where the opposite side is the same color as the observed side):
Total favorable outcomes = 2 + 2 = 4.
The probability is calculated as:
$ P(\text{Opposite side is same color}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} $
$ P(\text{Opposite side is same color}) = \frac{4}{6} $
Simplifying the fraction:
$ P(\text{Opposite side is same color}) = \frac{2}{3} $
If the data are skewed, which option of central tendency measure is the most unreliable indicator?
Events A, Band C are mutually exclusive events such that \(P(A) = \dfrac{3x + 1}{3}, P(B) = \dfrac{1-x}{4}\)and \(P(C) = \dfrac{1-2x}{4}\)The set of possible values of x are in the interval
Let A, B be two events in a discrete probability space with ℙ(A) > 0 and ℙ(B) > 0. Which of the following are necessarily true?
The Excess Kurtosis of the Geometric distribution with parameter p is:
For a distribution, the mean is 10, variance is 16, γ 1is + 1 and β 2is 4. The distribution is: