There are four friends Sharayn, Pinky, Tanisha and Mamta. Two study in J college. one each in X college and A college. Each one is definitely good at one subject and one is good at all the subjects. The subjects are English, Science, Maths and Computers. Of those studying in J college, one is good at Maths and the other in all subjects. Tanisha is studying in Acollege. Pinky is good at Maths. Sharayn is not good at Science. Find who is good at all the subjects.
Mamta
Solving the Friends, Colleges, and Subjects Logic Puzzle
This problem is a logic puzzle that requires careful deduction based on the given clues about four friends, their colleges, and their subject expertise.
Understanding the Entities and Attributes
- Friends: Sharayn, Pinky, Tanisha, Mamta
- Colleges: J college (2 students), X college (1 student), A college (1 student)
- Subjects: English, Science, Maths, Computers. One person is good at 'All' subjects.
Analyzing the Clues
Let's list the given clues:
- Two friends study in J college, one in X college, and one in A college.
- Each friend is good at one subject, except for one who is good at all subjects.
- Of those studying in J college, one is good at Maths and the other is good in all subjects.
- Tanisha is studying in A college.
- Pinky is good at Maths.
- Sharayn is not good at Science.
Step-by-Step Deduction
We can use the clues to determine the college and subject for each friend.
Step 1: Locate Tanisha
Clue 4 states that Tanisha is studying in A college. Since only one person is in A college, Tanisha is that person.
Current Status:
- Tanisha: A college, Subject ?
- Remaining Colleges: J college (2 spots), X college (1 spot)
- Remaining Friends: Sharayn, Pinky, Mamta
Step 2: Locate Pinky and Identify Her Subject
Clue 5 states that Pinky is good at Maths.
Clue 3 states that of the two people in J college, one is good at Maths and the other is good at all subjects.
Since Pinky is good at Maths, and one person in J college is good at Maths, Pinky must be one of the two students in J college.
Current Status:
- Tanisha: A college, Subject ?
- Pinky: J college, Good at Maths
- Remaining Colleges: J college (1 spot), X college (1 spot)
- Remaining Friends: Sharayn, Mamta
Step 3: Identify the Second Student in J College
We know two students are in J college. Pinky is one of them, and she is good at Maths. Clue 3 says the other student in J college is good at all subjects.
The remaining friends are Sharayn and Mamta. One of them must be the second student in J college (good at all subjects), and the other must be the student in X college.
Let's consider the possibilities for the person good at all subjects:
- Could Sharayn be good at all subjects (and thus in J college)?
- Could Mamta be good at all subjects (and thus in J college)?
Step 4: Use Sharayn's Subject Information (Clue 6)
Clue 6 states that Sharayn is not good at Science.
If someone is good at 'All' subjects, they are by definition good at Science (as Science is one of the subjects).
Since Sharayn is *not* good at Science, Sharayn cannot be good at all subjects.
Step 5: Conclude Who is Good at All Subjects
We established that the second person in J college is good at all subjects, and this person is either Sharayn or Mamta. We've deduced that Sharayn cannot be good at all subjects because she is not good at Science.
Therefore, the only remaining possibility is that Mamta is the friend who is good at all subjects. Mamta must be the second person in J college.
Summary of Findings
| Friend | College | Subject(s) |
|---|---|---|
| Pinky | J college | Maths |
| Tanisha | A college | ? (Not Maths, Not All) |
| Mamta | J college | All Subjects |
| Sharayn | X college | ? (Not Science, Not Maths, Not All) |
Based on this deduction, Mamta is the friend who is good at all the subjects and studies in J college along with Pinky.
Revision Table for Logic Puzzles
When solving logic puzzles, it's helpful to keep track of possibilities and eliminations. A table is often useful.
| Friend | College: J (2) | College: X (1) | College: A (1) | Subject: English | Subject: Science | Subject: Maths | Subject: Computers | Subject: All |
|---|---|---|---|---|---|---|---|---|
| Sharayn | ? | ✓ (Deduced) | X (A is Tanisha) | ? | X (Clue 6) | X (Maths is Pinky) | ? | X (Cannot be good at All if not good at Science) |
| Pinky | ✓ (Deduced) | X (J or A) | X (A is Tanisha) | X (Good at Maths) | X (Good at Maths) | ✓ (Clue 5) | X (Good at Maths) | X (Good at Maths) |
| Tanisha | X (A college) | X (A college) | ✓ (Clue 4) | ? | ? | X (Maths is Pinky) | ? | X (In A, not J) |
| Mamta | ✓ (Deduced) | X (Sharayn is in X) | X (A is Tanisha) | X (Good at All) | X (Good at All) | X (Good at All) | X (Good at All) | ✓ (Deduced) |
Additional Information on Deductive Reasoning
Logic puzzles like this one are solved using deductive reasoning. This involves starting with general statements or clues and applying them to specific situations to reach a certain conclusion.
- Identify all the known facts and constraints.
- Look for the most restrictive clues first, as they often limit possibilities significantly (like "Tanisha is studying in A college" and "only one person is in A college").
- Use elimination to rule out possibilities that contradict the clues.
- Chain clues together (e.g., Pinky is good at Maths, and one person in J is good at Maths, so Pinky is in J).
- If needed, consider hypothetical scenarios (like assuming Sharayn is good at all subjects) and see if they lead to contradictions based on other clues. If a scenario leads to a contradiction, it must be false.
Practicing different types of logic puzzles helps improve problem-solving and critical thinking skills.
Important Questions from Double Lineup
Radha wears five different coloured clothes, red, green, yellow, purple and brown, on five different days of a week, from Monday to Friday. She wears red clothes on
Wednesday. She does not wear green and brown clothes on Monday or Friday. She wears green clothes on the next day of wearing yellow clothes. On which day does she
wear brown clothes?Six friends, Anitha, Punitha, Chithra, Deepthi, Harini and Vani, are sitting in a field. Anitha and Punitha are from the Green house, whereas the rest belong to the Red house. Deepthi and Vani are tall. Whereas the others are short. Anitha, Chithra and Deepthi are wearing sarees. whereas the others are wearing frocks.
Who among them is tall and from the Red house but not wearing a saree?In a private school, there were five teachers. Abi and Geetha were teaching French and English. Harini and Geetha were teaching English and Science. Diva and Abi were teaching Maths and French. Hema and Geetha were teaching Social Science and French. Which subject is taught by the maximum number of teachers?
J, K, L, M, N and O are six teachers. Each one teaches a different subject out of Hindi, English, Math, Science, Social Science and Arts, not necessarily in the same order. Each of them teaches on only one day, from Monday to Saturday, not necessarily in the same order. J teaches Arts on Saturday. L teaches neither English nor Social Science, but he teaches on Thursday. Wednesday is reserved for Maths taught by K. O teaches Science a day before N. Social Science is taught a day before Arts.
Which subject is taught on the day between Social Science and Math?
J, K L, M, N and O are six teachers. Each one teaches a different subject out of Hindi, English, Math, Science, Social Science and Arts, NOT necessarily in the same order. Each of them teaches on only one day, from Monday to Saturday. NOT necessarily in the same order. J teaches Arts on Saturday. L teaches neither English nor Social Science, but he teaches on Thursday. Wednesday is reserved for Maths taught by K. O teaches Science a day before N. Social Science is taught a day before Arts. Who teaches Social Science?
