This question involves determining the seating order of five boys (P, Q, R, S, T) based on relative positional clues. All boys are facing North. Let's break down the clues to find the arrangement:
Now, let's combine these partial arrangements:
So, the final seating order from left to right is S, Q, P, T, R.
The row consists of five boys in the following order:
Left <-> Right:
| S (Position 1) | Q (Position 2) | P (Position 3) | T (Position 4) | R (Position 5) |
With five people in the row, the middle position is the 3rd spot. Looking at the arrangement $S Q P T R$, the boy in the 3rd position is P.
| Drugs added | No. of colonies | Drugs added | No. of colonies |
|---|---|---|---|
| A | 1156 | CD | 786 |
| B | 1148 | ABC | 30 |
| C | 1161 | ABD | 42 |
| D | 1139 | ACD | 630 |
| AB | 46 | BCD | 36 |
| AC | 640 | ABCD | 30 |
| AD | 942 | ||
| BC | 51 |
Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Q has an exam on Thursday and U has an exam on Saturday. T has an exam immediately before S. P has an exam on one of the days after V. R has an exam immediately after S. How many people have exams between R and P?