There are 90 coins, comprising 5 and 10 paisa coins. The value of all the coins is Rs. 7. How many 5 paisa coins are there? A. 50 B. 45 C. 40
C
This problem involves a collection of coins with different denominations and a total value. We need to find out exactly how many coins of a specific denomination are present. We can solve this by setting up a system of linear equations.
We are given:
The goal is to find the number of 5 paisa coins.
Let's use variables to represent the unknown quantities:
From the given information, we can form two equations:
This gives us the equation:
\[ x + y = 90 \quad \text{(Equation 1)} \]First, convert the total value to paisa: Rs. 7 = \(7 \times 100\) paisa = 700 paisa.
The value from \(x\) five paisa coins is \(5x\) paisa.
The value from \(y\) ten paisa coins is \(10y\) paisa.
The total value in paisa is the sum of these values:
\[ 5x + 10y = 700 \quad \text{(Equation 2)} \]Now we have a system of two linear equations with two variables \(x\) and \(y\).
\[ x + y = 90 \] \[ 5x + 10y = 700 \]We can solve this system using the substitution method. From Equation 1, we can express \(y\) in terms of \(x\):
\[ y = 90 - x \]Now, substitute this expression for \(y\) into Equation 2:
\[ 5x + 10(90 - x) = 700 \]Distribute the 10 on the left side:
\[ 5x + 900 - 10x = 700 \]Combine the \(x\) terms:
\[ 900 - 5x = 700 \]Subtract 900 from both sides of the equation:
\[ -5x = 700 - 900 \] \[ -5x = -200 \]Divide both sides by -5 to solve for \(x\):
\[ x = \frac{-200}{-5} \] \[ x = 40 \]So, the number of 5 paisa coins is 40.
We can also find the number of 10 paisa coins (\(y\)) using Equation 1:
\[ y = 90 - x = 90 - 40 = 50 \]There are 40 five paisa coins and 50 ten paisa coins. Let's check the total value:
\((40 \text{ coins} \times 5 \text{ paisa/coin}) + (50 \text{ coins} \times 10 \text{ paisa/coin}) = 200 \text{ paisa} + 500 \text{ paisa} = 700 \text{ paisa}\).
Since 700 paisa is equal to Rs. 7, our solution is correct.
The number of 5 paisa coins is 40.
| Concept | Description | Relevance to Coin Problems |
|---|---|---|
| System of Linear Equations | A set of two or more linear equations involving the same variables. | Coin problems often require two equations (one for quantity, one for value) to solve for two unknowns (number of each coin type). |
| Variables | Symbols (like \(x\) and \(y\)) used to represent unknown quantities. | Used to represent the number of each type of coin. |
| Setting up Equations | Translating words from the problem into mathematical expressions and equations. | Crucial step to model the relationships between coin quantities and values. |
| Solving Methods | Techniques like substitution or elimination used to find the values of variables in a system of equations. | Necessary to find the actual number of each coin type. |
Coin problems are a common type of word problem that can be solved using linear equations. Here are some related concepts:
A man has equal number of five, ten and twenty rupee notes amounting to Rs. 385. Find the total number of notes?
The sum of three consecutive number is 126. Find the highest number?
Simplify 5x(x + 2) + 4x
A.5x 2+ 10
B.9x + 10
C.5x 2- 14x
D.5x 2+ 14xSolve:
x - 4 = -3
A. 7
B. -1
C. -7
D. 1
If 4(3x - 2) = 2(3x + 8), Then x = ?
A. 1
B. 2
C. 3
D. 4