The wire loop PQRSP formed by joining two semicircular wires of radii R1 & R2 carries a current I as shown in the figure. The magnitude of the magnetic field at the centre 'C' is:
(μ0I / 4) (1/R1 - 1/R2)
The magnetic field at the center (C) of a circular loop due to a semicircle of radius R carrying current I is given by:
B = (μ0 I) / (4R).
- The two semicircles have radii R1 and R2, and they carry current in opposite directions.
- The net magnetic field at C is obtained by subtracting the fields due to the two semicircles:
B = (μ0I / 4) (1/R1 - 1/R2).
Thus, the correct answer is (d).
Important Questions from Electromagnetic Induction
The half-life period of a radioactive element 'X' is same as the mean life of another radioactive element Y. Initially both of them have the same no. of atoms, then:
A. X and Y have the same decay rate initially.
B. X and Y decay at the same rate always.
C. Y will decay at a faster rate than X.
D. X will decay at a faster rate than Y.
Choose the correct answer from the options given below:
A Neutron is moving with a velocity of V in a non-uniform magnetic field as shown in the figure.
Velocity v̅ of neutron would be:
The graph between resistivity and temperature given below can be for the material:
Which phenomenon proves the particle nature of photons?
A semiconductor device is connected in series circuit with a battery and resistance. A current is found to pass through the circuit. If the polarity of the battery is reversed, the current chops at almost zero. The device may be:
