Lower half of a convex lens is made opaque. Which of the following statements describes the image of the object placed in front of the lens?
Intensity of image gets reduced
A convex lens forms an image by refracting light rays from an object. Rays originating from a point on the object pass through different parts of the lens and converge at a corresponding point in the image plane (for a real image) or appear to diverge from a point (for a virtual image).
Consider light rays from a single point on the object. These rays spread out and strike the entire surface of the lens (or at least the part of the lens through which they can pass). The lens then refracts these rays such that they converge to form the image of that specific point.
When the lower half of a convex lens is made opaque, it means that light rays that would have passed through the lower half are now blocked. However, rays from every point on the object can still pass through the upper half of the lens.
While the entire image is still formed, blocking a portion of the lens reduces the total amount of light that passes through the lens and reaches the image plane. The brightness or intensity of an image is directly proportional to the amount of light energy received per unit area.
Since fewer light rays contribute to forming the image, the image will be less bright compared to when the entire lens is unblocked. This reduction in brightness is described as a reduction in the intensity of the image.
Let's examine the given options:
Therefore, when the lower half of a convex lens is made opaque, the intensity of the image gets reduced, but the entire image is still formed.
| Property | Unblocked Convex Lens | Convex Lens with Half Blocked |
|---|---|---|
| Image Formation | Complete image formed | Complete image formed |
| Image Size/Magnification | Depends on object position | Same as unblocked lens (for same object position) |
| Image Nature (Real/Virtual) | Depends on object position | Same as unblocked lens (for same object position) |
| Image Position | Depends on object position and lens formula | Same as unblocked lens (for same object position) |
| Image Brightness/Intensity | Maximum intensity (for a given lens) | Reduced intensity (less light passes through) |
The intensity of the image formed by a lens is related to the amount of light collected by the lens from the object. The effective area of the lens that allows light to pass through is called the aperture. When a part of the lens is blocked, the effective aperture area is reduced.
Mathematically, the intensity of the image is proportional to the square of the diameter of the lens aperture (or the area of the aperture). If half the lens is blocked, the area through which light passes is roughly halved (assuming uniform blocking). This reduction in the amount of light leads to a dimmer image.
It's important to remember that every part of the lens contributes to forming the image of every point on the object. This is why blocking a part of the lens doesn't remove a corresponding part of the image, but rather makes the entire image less bright.
In a pair of adjacent coils, for a change of current in one of the coils from 0 A to 10 A in 0.25 s, the magnetic flux in the adjacent coil changes by 15 Wb. The mutual inductance of the coils is:
A 50 Hz AC current of crest value 1 A flows through the primary of a transformer. If the mutual inductance between the primary and secondary is 0.5 H, the crest voltage induced in the secondary is:
A long solenoid of diameter 0.1 m has 2 × 104 turns per meter. At the center of the solenoid, a coil of 100 turns and radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to 0 A from 4 A in 0.05 s. If the resistance of the coil is 10π² Ω, then the total charge flowing through the coil during this time is:
A transformer has an efficiency of 80%. It works at 3 kW and 120 V. If the secondary voltage is 240 V, what will be the secondary current?
In an AC generator when the plane of the armature is perpendicular to the magnetic field, what will the magnitude of the magnetic flux passing through the coil and the emf induced in the coil be?