Problem: Find the new volume of a sphere when its radius is doubled, given the initial volume is $288\pi \text{ cm}^3$. Correct Answer: $2304\pi \text{ cm}^3$.
The volume ($V$) of a sphere is related to its radius ($r$) by the formula $V = \frac{4}{3}\pi r^3$. This means the volume is proportional to the cube of the radius ($V \propto r^3$).
If the radius is scaled by a factor $k$, the volume is scaled by a factor of $k^3$. In this problem, the radius is doubled, so the scaling factor $k=2$. Therefore, the volume is multiplied by $k^3 = 2^3 = 8$.
Given: Initial Volume ($V_{initial}$) = $288\pi \text{ cm}^3$. The radius is doubled, so the scaling factor $k=2$.
Calculation: New Volume ($V_{new}$) = Initial Volume $\times k^3$ $V_{new} = 288\pi \times (2)^3$ $V_{new} = 288\pi \times 8$ $V_{new} = 2304\pi \text{ cm}^3$
When the radius of the sphere is doubled, the new volume is $2304\pi \text{ cm}^3$. This matches Option B.