To find the reverse breakdown voltages of the zener diodes \(Z_1\) and \(Z_2\), let us analyze the transfer characteristics shown on the oscilloscope and the given circuit.

The oscilloscope display shows the relationship between \(V_i\) (input voltage) and \(V_o\) (output voltage).

Important settings are given as:

• Oscilloscope X input: \(0.5 \, \text{V/div}\)
• Oscilloscope Y input: \(2 \, \text{V/div}\)

The op-amp is ideal and will saturate at the zener breakdown voltages.

Step-by-step Analysis

1. When \(V_i\) is zero, the beam is at the origin of the oscilloscope, based on standard condition. Hence, positive/negative saturation indicates zener breakdown.
2. From the graph, the output \(V_o\) becomes constant when the input \(V_i\) exceeds certain thresholds. These thresholds correspond to the zener breakdown voltages plus the diode forward voltage drop (0.7 V).
3. Count the grid divisions on the oscilloscope to determine the saturation points:
   • For \(Z_1\), \(V_i\) is shown at approximately 13.4 divisions. Since each division corresponds to \(0.5 \, \text{V}\), the \(V_i\) value is approximately \(13.4 \times 0.5 = 6.7 \, \text{V}\).
   • This indicates \(V_z1 + 0.7 = 6.7 \, \text{V}\), resulting in \(V_z1 = 6.0 \, \text{V}\).
   • For \(Z_2\), \(V_i\) is shown at approximately 9.4 divisions, indicating \(9.4 \times 0.5 = 4.7 \, \text{V}\).
   • This indicates \(V_z2 + 0.7 = 4.7 \, \text{V}\), resulting in \(V_z2 = 4.0 \, \text{V}\).

Thus, the reverse breakdown voltages of \(Z_1\) and \(Z_2\) in the given circuit are \(6.7\, \text{V}\\) and \(4.7\, \text{V}\\), respectively.

Therefore, the correct answer is: 6.7 V and 4.7 V.