The Zener resistance of a Zener diode, which exhibits 50 mV change in V zfor a 2.5 mA change in I zis _________.
20 Ω
The Zener resistance ($R_z$) of a Zener diode is a measure of how much the Zener voltage changes with respect to a change in Zener current in the breakdown region. It is essentially the dynamic resistance of the diode operating in its reverse breakdown mode.
The formula for Zener resistance is given by the ratio of the change in Zener voltage ($\Delta V_z$) to the corresponding change in Zener current ($\Delta I_z$):
\[ R_z = \frac{\Delta V_z}{\Delta I_z} \]
In this question, we are given the following values:
First, we need to convert these values to standard units (Volts and Amperes):
Now, we can substitute these values into the formula for Zener resistance:
\[ R_z = \frac{50 \times 10^{-3} \text{ V}}{2.5 \times 10^{-3} \text{ A}} \]
We can cancel out the \(10^{-3}\) terms from the numerator and the denominator:
\[ R_z = \frac{50}{2.5} \text{ } \Omega \]
Performing the division:
\[ R_z = 20 \text{ } \Omega \]
Therefore, the Zener resistance of the diode is \(20 \text{ } \Omega\).
Which of the following diodes operate(s) in reverse breakdown region?
Zener diodes are used as _______.
Zener diode works under which region of V - I characteristics of the semiconductor diode?
A properly doped crystal diode which has a sharp breakdown voltage is known as _______
A Zener diode has: