College A B C D E Demand (application received) 3000 600 2500 1200 3300 Intake (available seats) 1500 1800 1000 2700 2200
This problem requires us to compare the total student demand for the two colleges with the highest demand against the total demand for the two colleges with the lowest demand, based on the provided table. We need to calculate the percentage by which the higher total demand exceeds the lower total demand.
Data Analysis and Identification
First, let's list the demand for each college from the table:
| College | A | B | C | D | E |
| Demand (applications received) | 3000 | 600 | 2500 | 1200 | 3300 |
Identifying Highest and Lowest Demand Colleges
We need to find the two colleges with the highest demand and the two colleges with the lowest demand.
- Ordering the colleges by demand in descending order:
- College E: 3300 (Highest)
- College A: 3000 (Second Highest)
- College C: 2500
- College D: 1200 (Second Lowest)
- College B: 600 (Lowest)
Calculating Total Demand
Now, we calculate the total demand for these groups:
- Total demand of the two highest demanded colleges (College E and College A):
- $ \text{Total Demand}_\text{Highest} = 3300 + 3000 = 6300 $
- Total demand of the two lowest demanded colleges (College B and College D):
- $ \text{Total Demand}_\text{Lowest} = 600 + 1200 = 1800 $
Calculating Percentage Higher
The question asks what percent higher the total demand of the two highest demanded colleges is than the total demand of the two lowest demanded colleges. We use the formula for percentage increase:
$ \text{Percentage Higher} = \left( \frac{\text{Total Demand}_\text{Highest} - \text{Total Demand}_\text{Lowest}}{\text{Total Demand}_\text{Lowest}} \right) \times 100 $
Substituting the values we found:
$ \text{Percentage Higher} = \left( \frac{6300 - 1800}{1800} \right) \times 100 $
$ \text{Percentage Higher} = \left( \frac{4500}{1800} \right) \times 100 $
Simplify the fraction:
$ \frac{4500}{1800} = \frac{45}{18} $
Divide both numerator and denominator by their greatest common divisor, which is 9:
$ \frac{45 \div 9}{18 \div 9} = \frac{5}{2} $
Convert the fraction to a decimal:
$ \frac{5}{2} = 2.5 $
Now, multiply by 100 to get the percentage:
$ \text{Percentage Higher} = 2.5 \times 100 = 250\% $
Conclusion
Therefore, the total demand of the two highest demanded colleges is 250% higher than the total demand of the two lowest demanded colleges.
Important Questions from Data Interpretation
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The total runs scored by four cricketers P, Q, R, and S in years $2009$ and $2010$ are given in the following table:
Player $2009$ $2010$ P $802$ $1008$ Q $765$ $912$ R $429$ $619$ S $501$ $701$
The player with the lowest percentage increase in total runs isStudy the given table and answer the following question:
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The table below shows the number of toys of 6 different colours sold from a shop during a given period. The table also shows the percentage of toys of each colour which are cars.
Colour Total toys Percentage of cars C1 500 12 C2 600 15 C3 400 12.5 C4 550 10 C5 650 20 C6 450 10 What is the total number of car toys of C2 and C3 taken together?
