The theoretical density of a metallic solid crystal structure is given by: \( \rho = \frac{nA}{V_C N_A} \) where \( n \) is the number of atoms associated with each unit cell, \( A \) is atomic weight, \( V_C \) is the volume of the unit cell, and \( N_A \) represents
The theoretical density of a metallic solid crystal structure is a fundamental property that relates the mass of atoms within a unit cell to the volume of the unit cell. The formula provided is a standard way to calculate this density:
\( \rho = \frac{nA}{V_C N_A} \)
Let's break down each term in this formula to understand its meaning:
The term \( N_A \) in the formula converts the atomic weight (mass per mole) into the mass per atom when considered within the unit cell context. Specifically, atomic weight (\( A \)) is the mass of one mole of atoms. A mole is defined as containing a specific number of elementary entities (like atoms or molecules).
This specific number is known as Avogadro's number. Avogadro's number is defined as the number of constituent particles, usually atoms or molecules, that are contained in one mole of a given substance. Its approximate value is \(6.022 \times 10^{23}\) particles per mole.
In the context of the theoretical density formula, \( N_A \) is used to convert the atomic weight \( A \) (in g/mol) into the mass of 'n' atoms within the unit cell. The mass of 'n' atoms is \( n \times \frac{A}{N_A} \). Dividing this mass by the volume of the unit cell \( V_C \) gives the density:
\( \rho = \frac{n \times (A / N_A)}{V_C} = \frac{nA}{V_C N_A} \)
Therefore, \( N_A \) represents Avogadro's number.
Let's look at the given options for what \( N_A \) represents:
Force is a physical interaction that can change the motion of an object. It is measured in Newtons (N). This is unrelated to the number of atoms in a mole.
While Avogadro's number is a number of particles, the term "number of particles" is too general. \( N_A \) specifically refers to the number of particles in a mole.
This matches our understanding. Avogadro's number is the specific constant used to relate the number of atoms or molecules to the macroscopic quantity of a mole.
Number of turns is a term used in contexts like coils or screws. It is unrelated to crystal structures or density calculations.
Based on the analysis of the formula and the options, \( N_A \) represents Avogadro's number.
| Term | Represents | Typical Unit |
|---|---|---|
| \( \rho \) | Theoretical Density | g/cm\(^3\) |
| \( n \) | Number of atoms per unit cell | Dimensionless |
| \( A \) | Atomic Weight (Molar Mass) | g/mol |
| \( V_C \) | Volume of the unit cell | cm\(^3\)/unit cell |
| \( N_A \) | Avogadro's number | atoms/mol (or particles/mol) |
| Concept | Description |
|---|---|
| Unit Cell | The smallest repeating structural unit in a crystal lattice. |
| Theoretical Density (\(\rho\)) | Mass of atoms in a unit cell divided by the volume of the unit cell. Represents the expected density assuming a perfect crystal lattice. |
| Atomic Weight (\(A\)) | The mass of one mole of an element's atoms. |
| Avogadro's Number (\(N_A\)) | The number of constituent particles (atoms, molecules, etc.) in one mole of a substance, approximately \(6.022 \times 10^{23}\) particles/mol. |
| Number of atoms per unit cell (\(n\)) | Depends on the crystal structure type (e.g., BCC \(n=2\), FCC \(n=4\), Simple Cubic \(n=1\)). |
To calculate the theoretical density of a metallic element, you need the following information:
The volume of the unit cell (\( V_C \)) depends on the crystal structure and lattice parameter ('a'):
Note that for BCC and FCC, the lattice parameter 'a' is related to the atomic radius 'r' differently: For BCC, \( a = \frac{4r}{\sqrt{3}} \); for FCC, \( a = \frac{4r}{\sqrt{2}} \). For SC, \( a = 2r \). These relationships are used if the atomic radius is given instead of the lattice parameter.
Once \( n \), \( A \), \( V_C \), and \( N_A \) are known, the theoretical density \( \rho \) can be calculated using the formula \( \rho = \frac{nA}{V_C N_A} \).
What is the maximum depth to which a trench of vertical sides can be excavated in a clay stratum with c = 50 kN/m², y = 16 kN/m³, β = 90°, ¢ = 0°, Fc = 1 and N = 0-261?